All categories

2 years ago

Simplify.

Mathematics

2 answers:

AVprozaik [17]2 years ago

4 0

Answer:

A. 0

Step-by-step explanation:

Softa [21]2 years ago

3 0

Answer:

√12-2/5×√75

2√2-2/5×5√3

2√2-2√3

2(√(2×3)

2√6

You might be interested in

15 is 60% of what number?

vlada-n [284]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help i suck at math

KatRina [158]

Answer:

its 2 inches

Step-by-step explanation:

0.5 * 16= 4 * x

8 = 4x

x = 2

3 0

2 years ago

Read 2 more answers

Find the missing side of the triangle

Ivanshal [37]

Answer:

25 in

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Identify

Leg a = 24

Leg b = 7 in

Leg c = x

Step 2: Solve for x

Substitute in variables [Pythagorean Theorem]: 24² + 7² = x²
Evaluate exponents: 576 + 49 = x²
Add: 625 = x²
[Equality Property] Square root both sides: 25 = x
Rewrite/Rearrange: x = 25

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

3 years ago

Help me with the question

Norma-Jean [14]

Answer:

Step-by-step explanation:

B is the only one that is actually a point on the graph

3 0

3 years ago