Which of the following is the minimum value of the equation y = 2x2 + 5?

1 answer:

4 0

(0, 5) is the minimum value.

Find the axis of symmetry by plugging the respective variables into -b/2a

-5/2(0) = 0

There is no b-value in our equation, or rather, the value of b is 0. To see this, y = 2x^2 + 5 can be written as

y = 2x^2 + 0x + 5

We plug 0 into f(x), establishing every x-value as 0.

f(0) = 2(0)^2 + 5
f(0) = 0 + 5
f(0) = 5

5 is now your vertex’s y-value. Plot the two values together.

(0, 5)

We know that this is a minimum because the leading coefficient is positive, meaning the the graph’s parabola will open down.

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Now, according to the question:

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<h3>How to derive the equation of the axis of symmetry </h3>

In this question we know the locations of two points with the same y-value, which means that the axis of symmetry is parallel to the y-axis and that both points are equidistant. Thus, the axis of symmetry passes through the midpoint of the line segment whose ends are those points.