Answer:
16
Step-by-step explanation:
+++
16
Given :
- A = {x: 2x² + 3x - 2 = 0 }
- B = {x : x² + 3x - 4 = 0 }
To find :
Solution :-
<u>The </u><u>first </u><u>set </u><u>is </u><u>,</u>
- A ={x : 2x² + 3x - 2 = 0}
<u>Solving</u><u> </u><u>the </u><u>Quadratic</u><u> equation</u><u> </u><u>,</u>
- 2x² + 3x - 2 = 0
- 2x² + 4x - x - 2 = 0
- 2x( x + 2) -1( x + 2 ) = 0
- (2x -1) ( x + 2) = 0
- x = 0.5 , -2
<u>Hence</u><u> </u><u>,</u>
<u>The </u><u>second</u><u> </u><u>set </u><u>is </u><u>,</u>
- B ={ x :x² + 3x - 4 = 0 }
<u>Solving</u><u> the</u><u> Quadratic</u><u> equation</u><u> </u><u>,</u>
- x² + 3x - 4 = 0
- x² + 4x - x - 4 = 0
- x( x + 4)-1 ( x +4) = 0
- (x + 4) ( x -1) = 0
- x = 1 , -4
<u>Hence</u><u> </u><u>,</u>
<u>Now </u><u>,</u>
- A U B = { 0.5 , 1 , 4 , -2}
- A Π B = {∅ }
Since AΠ B is a null set , hence ,
Answer:
(x - 3)^2 + (y + 1) = 25
Step-by-step explanation:
First find the midpoint of the diameter, because that represents the center of the circle.
-1 + 7
The x-coordinate of the midpoint is xm = ---------- = 3
2
2 - 4
and the y-coordinate is ym = ---------- = -1
2
And so the center of this circle is at (3, -1).
Use the Pythagorean Theorem to determine the square of the radius:
square of radius = 4^2 + (-3)^2 = 16 + 9 = 25
And so the equation of this circle is (x - 3)^2 + (y + 1) = 25
Answer: second option.
Step-by-step explanation:
You must apply 
Then, given the right triangle and the angle D, the opposite side and the hypotenuse of the triangle are the following:
Therefore, when you substitute values, you have:
Reduce the fraction, then you obtain:
