The largest angle of the quadrilateral PQRS is 120°
<u>Step-by-step explanation:</u>
Given that

3P=2Q (1)
4Q=3R
Q=3R/4
Substitute the value of <Q in (1)

<P=3R/6=R/2
Comparing (1) and (2)
we get 6P=4Q=3R
In a cyclic quadrilateral, opposite angles are supplementary i.e their sum is 180 degree
<P and <R are opposite angles.
Hence 
<R/2+<R=180


<S and <Q are opposite angles. Hence
<S=180-<Q=180-90=90°
<P=60°
<Q=90°
<R=120°
<S=90°
The largest angle of the quadrilateral is 120°(<R)
15.31535524 i think hope this helped
Look at point (-3,-1) on triangle I. The corresponding point on triangle II is (-4, 1). X moved 1 to the left, so a -1 will go in the box for x. Y moved up 2, so a 2 will go in the box for y.
Answer:
acceleration
Step-by-step explanation:
i hope this is right
Answer:
3000
Step-by-step explanation:
it is very simple as the number's hundredth place is more than 5 , hence , it will be rounded up to nearest greater number.
in our case, it is 3000