Answer:
The answer is D good luck :)
-2<em>x</em> + 6<em>y</em> = -38
3<em>x</em> - 4<em>y</em> = 32
To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.
3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114
2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64
Add the equations.
-6<em>x </em>+ 18<em>y</em> = -114
6<em>x</em> - 8<em>y</em> = 64
+_____________
0 + 10<em>y</em> = -50
10<em>y</em> = -50
<em>y</em> = -5
Substitute -5 for y into one of the original equations to find x.
3<em>x</em> - 4<em>y</em> = 32
3<em>x</em> - 4(-5) = 32
3<em>x</em> + 20 = 32
3<em>x</em> = 12
<em>x</em> = 4
Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.
-2<em>x</em> + 6<em>y</em> = -38
-2(4) + 6(-5) = -38
-8 - 30 = 38
38 = 38
3<em>x</em> - 4<em>y</em> = 32
3(4) - 4(-5) = 32
12 + 20 = 32
32 = 32
Answer:
<em>x</em> = 4 and <em>y</em> = -5; (4, -5).
Answer:
The answer to the question is
The actual duration of the trip is 8/9 times the normal duration or the bus arrived 1/9 times earlier than it would have at a constant speed of v kph
Step-by-step explanation:
Speed of bus in the first third distance = v kph
Speed of bus for the remaining two thirds = 1.2 v kph
To solve the question, we note that speed = distance/time
therefore time = distance/speed
Let the distance of the destination be D, then
Normal duration at speed v = D/v
Actual duration (D/3)÷v + (2D/3)÷(1.2v) ⇒ (1.2*D/3 + 2D/3)1.2v
=
= (8/9)×D/v
Therefore the actual duration is 8/9 times the normal duration
so from accidental deaths we have
30 from falls
47 from fires
200 from drowning
1950 car accidents
so the total of those is 30+47+200+1950, or 2227.
the ones that weren't car accidents will be 2227 - 1950, or 277.
if we take 2227 to be the 100%, how much is 277 off of it in percentage?

Answer:
5 • (4xy + 2x - 3y)
Step-by-step explanation: