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3 years ago

6

a rectangular prism 1/4 centimeter long, 4 centimeters wide, and 1/2 centimeter high. What is the volume, in cubic centimeters,

of the rectangular prism?

1 answer:

Hoochie [10]3 years ago

7 0

Answer:

0.5cm^3

Step-by-step explanation:

volume of rectangular prism= length x width x height

1/4cm x 1/2cm x 4cm =

0.25cm x 0.5cm x 4cm =

0.5cm^3

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The table summarizes the scoring of a football game between Team A and Team B. A touchdown (TD) is worth 6 points, a field goal

Anit [1.1K]

If you would like to find the final score, you can do this using the following steps:

Team A: 6 points * 3 + 3 points * 2 + 2 points * 1 + 1 point * 0 = 6 * 3 + 3 * 2 + 2 * 1 + 1 * 0 = 18 + 6 + 2 + 0 = 26 points
Team B: 6 points * 4 + 3 points * 4 + 2 points * 1 + 1 point * 2 = 6 * 4 + 3 * 4 + 2 * 1 + 1 * 2 = 24 + 12 + 2 + 2 = 40 points

The final score of team A is 26 points and the final score of team B is 40 points.

3 0

3 years ago

Centerville is the headquarters of Greedy Cablevision Inc. The cable company is about to expand service to two nearby towns, Spr

NeX [460]

Answer:

20.2057 Units.

Step-by-step explanation:

First, we determine the length of the cable.

Distance between Centerville (8,0) and point (x,0) is given as:

$\sqrt{(8-x)}^2=8-x$

Distance between point (x,0) and Springfield(0,7) is:

$\sqrt{(7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Distance between point (x,0) and Shelvyfield(0,-7) is:

$\sqrt{(-7-0)^2+(0-x)^{2}}=\sqrt{(7)^2+(x)^{2}}$

Therefore the Length of the Cable L(x)

$L(x)=(8-x)+2\sqrt{(7)^2+(x)^{2}}$

To find the critical point, we set the derivative of L(x)=0

$L^{'}(x)=-1+\frac{2x}{\sqrt{\left( 49 - x^{2}\right) }}$

$\frac{-\sqrt{\left( 49 - x^{2}\right)}+2x}{\sqrt{\left( 49 - x^{2}\right)}}=0\\-\sqrt{\left( 49 - x^{2}\right)}+2x=0\\\sqrt{\left( 49 - x^{2}\right)}=2x\\(\sqrt{\left( 49 - x^{2}\right)})^2=(2x)^2\\49 - x^{2}=4x^2\\49=5x^2\\x^2=\frac{49}{5}\\x= 3.1305$

To verify that L(x) has a minimum at this critical number we compute the second derivative L″(x) and find its value at the critical number.

$L^{''}(x)=\frac{\left( 98\right) \,\sqrt{\left( 49 - x^{2}\right) }}{{\left( 7 - x\right) }^{2}\,{\left( 7+x\right) }^{2}}\\At \:x=3.1305, L^{''}=0.3993$

Since $L^{''}(x)$ is positive, the minimum point of L(x) exists.

Next, we find the minimum length by substituting z=3.1305 into L(x)

$L(3.1305)=(8-3.1305)+2\sqrt{(7)^2+(3.1305)^{2}}$

Minimum Length, L=20.2057

The minimum length of the cable is 20.2057 Units.

6 0

2 years ago

- 3x – 4y= 2<br>3x + 3y = -3<br> how to solve the system of equations by substituting

PolarNik [594]

Answer: x=-2 Y=1

Step-by-step explanation: You convert the first equation to slope form then you take the second equation, so 3x+3y=-3 and you plug in the Y. So this would be 3x+3(-3/4-1/2)=-3. Then you would solve that equation and get the answer 3x-9/4x-3/2=-3. Now you combine like terms to get the answer 3/4x-3/2=-3 and you add 3/2 to both sides of the equation which leaves you with 3/4x=-3/2 now you solve for x and get -2. Now to find the y you take the first equation, that you converted to slope intercept form y=mx+b, and you plug in the x. Which would give you the problem, y=-3/4(-2)-1/2 then you get y=3/2-1/2 and you combine like terms to get the answer y=1

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3 years ago

2x + (14 + x^2) in ASSOCIATIVE PROPERTY<br> Pls

yanalaym [24]

Answer:

x^2+2x+14

Step-by-step explanation:

2x+(14+x^2)

2x+(x^2+14)

2x+x^2+14

x^2+2x+14

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3 years ago

Terry is an up-and-coming florist who specializes in weddings. He uses 5 roses, 3 daisies, and 4 bundles of green filler to make

weeeeeb [17]

If r is the cost of roses which he use 5 d is daisies which he used 3 and f is green filler and he used 4 the cost of 75 more is 234

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2 years ago

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