Ask question

Ask question

All categories

3 years ago

6

a rectangular prism 1/4 centimeter long, 4 centimeters wide, and 1/2 centimeter high. What is the volume, in cubic centimeters,

of the rectangular prism?

1 answer:

Hoochie [10]3 years ago

7 0

Answer:

0.5cm^3

Step-by-step explanation:

volume of rectangular prism= length x width x height

1/4cm x 1/2cm x 4cm =

0.25cm x 0.5cm x 4cm =

0.5cm^3

You might be interested in

3(5+3)^2 +14<br><br><br> help me pls i cannot deal w my parents again

Scilla [17]

Answer:

206

Step-by-step explanation:

I put it in a calculator

6 0

4 years ago

Read 2 more answers

If a > 0 and b < 0, then which of the following must be true.

slava [35]

<span>We need to find the correct answer on the given choices:

If a > 0 and b < 0, then The answer is a + b > 0
let’s give a specific example:
let’s have a = 1
and b = .20

</span> <span>Now, let’s try calculating if our answer is correct.
Thus a + b > 0
=> a + b
=> 1 + .20
=> 1.20
and 1.20 is greater than 0.
=>Therefore 1.20 > 0 = a + b > 0</span>

7 0

4 years ago

Doug is playing a game. He gets p points for green cards, 2p points for yellow cards, and 3p points for wild cards. He has 16 gr

Lera25 [3.4K]

B. 25+ 6p is your answer

8 0

3 years ago

F (x) = - eˣ Baseline (x - 4)<br> What is(are) the critical point(s) of f?

Ber [7]

Answer

given,

$f(x) = \dfrac{-e^x}{x - 4}$

to find the critical point of the given expression

fist differentiating the function

$f'(x) = -\dfrac{(x-4)e^x+ e^x}{(x - 4)^2}$

$f'(x) = \dfrac{-(x-4)e^x- e^x}{(x - 4)^2}$

$f'(x) = \dfrac{-e^x(x-3)}{(x - 4)^2}$

now equating differential equation to zero

$\dfrac{e^x(-x+3)}{(x - 4)^2}=0$

$e^x(-x+3)=0$

now,

-x + 3 = 0 and eˣ ≠ 0

x = 3

the critical number will be equal to x = 3

$y = \dfrac{-e^3}{3 - 4}$

$y =e^3$

8 0

4 years ago

Y = 4x + 2<br> y = -2x - 4

BlackZzzverrR [31]

Answer:

x = −1

y = −2

6 0

3 years ago