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stepladder [879]
3 years ago
15

Write the equation in slope intercept form given

Mathematics
2 answers:
Hatshy [7]3 years ago
7 0
The equation of the line is:
y = -4x -1


Work:
y = mx + b
y = -4x + b
3 = -4(-1) + b
3 = 4 + b
-1 = b
Rus_ich [418]3 years ago
7 0

Answer:

Step-by-step explanation:

if a straight line with a slop m pass through point P(x_o, y_o) it's equation is:

y-y_o=m(x-x_o)\\\\y-(3)=-4(x-(-1))

y=-4x-4+3\\\\y=-4x-1

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A circle has a circumference of 28.26 units. What is the diameter of the circle?
Karolina [17]

Answer:

The diameter of the circle is 9.

Step-by-step explanation:

Because circumference is equal to \pi * d, we can backtrack and use this equation to find diameter. Let's say \pi is equal to 3.14.

28.26 = 3.14d

Divide both sides by 3.14.

9 = d


The diameter of the circle is 9.


6 0
3 years ago
23×536=?<br>find the product
Contact [7]
The answer or product is 12328 
6 0
4 years ago
Read 2 more answers
Please help !! Will mark brainliest answer
Norma-Jean [14]

Answer:

x = 12

Step-by-step explanation:

18:24 (comparing the same sides for the similar shapes; 18 and 24) when simplified down is equal to 3:4.

Using this 3:4 scale factor we can find the missing side x.

Solving for x :

\frac{3}{4} × 16 = 12

x = 12

OR: Set up a proportion:

\frac{24}{16} × \frac{18}{x}

<em>cross-multiply</em>

16 × 18 = 288

24 × x = 24x

288 = 24x

x = 12

3 0
3 years ago
If 5&lt;2x+3&lt;11, what is the possible range of value of -4x-6
Lady bird [3.3K]

Answer:

-10 > (-4x - 6) > -22

Step-by-step explanation:

Given inequality is 5 < 2x + 3 < 11

Now we will multiply this inequality by (-2) resulting,

5(-2) > (2x + 3)(-2) > 11(-2)

-10 > (-4x - 6) > -22 (Sign of inequality gets reversed when the inequality is multiplied or divided by a negative number)

Therefore, the possible range of (-4x - 6) is between -22 and -10.

4 0
4 years ago
What is the following sum? Assume x20 and 20.<br> √√x²y³ +2√√x³y² + xy √√y
max2010maxim [7]

The value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

<h3>How to evaluate the sum?</h3>

The attachment represents the proper format of the question

The summation expression is given as:

\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y

Expand the radicands

\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y

Evaluate the square roots

xy\sqrt{y} + 2xy^2\sqrt{x} + xy\sqrt y

Add the like terms

2xy\sqrt{y} + 2xy^2\sqrt{x}

Hence, the value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

3 0
2 years ago
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