Answer:
If he spends $120 dollars a month, and he cut's that down to $50 a month, we should create a pattern to visualize the months.
Step-by-step explanation:
120- 50= 70 ($70 saved each month)
Month 1- $70 saved total
Month 2- $140 saved total
Month 3- $210 saved total
Month 4- $280 saved total
Month 5- $350 saved total
Month 6- $420 saved total
It takes 6 months to get 400 saved. We could also divide to get
5.714285, but it would takes 6 months before reaching the goal. :)
The slope-point form of line:
We have the points (-9, 7) and (6, 2). Substitute:
The slope-intercept form of line:
.
We have the slope m:
Pu the coordinates of the point (6, 2) to the equation:
<em>add 2 to both sides</em>
It’s C cash advances after the introductory period.
-23 - (-60) / 69 - 93 = 37 / -24
Answer:
z (min) = 360 x₁ = x₃ = 0 x₂ = 3
Step-by-step explanation:
Protein Carbohydrates Iron calories
Food 1 (x₁) 10 1 4 80
Food 2 (x₂) 15 2 8 120
Food 3 (x₃) 20 1 11 100
Requirements 40 6 12
From the table we get
Objective Function z :
z = 80*x₁ + 120*x₂ + 100*x₃ to minimize
Subjet to:
Constraint 1. at least 40 U of protein
10*x₁ + 15*x₂ + 20*x₃ ≥ 40
Constraint 2. at least 6 U of carbohydrates
1*x₁ + 2*x₂ + 1*x₃ ≥ 6
Constraint 3. at least 12 U of Iron
4*x₁ + 8*x₂ + 11*x₃ ≥ 12
General constraints:
x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 all integers
With the help of an on-line solver after 6 iterations the optimal solution is:
z (min) = 360 x₁ = x₃ = 0 x₂ = 3
