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3 years ago

7

A magazine rack contains 5 sports magazines, 7 news magazines, and 10 fashion magazines. After a magazine is chosen, it is not r

eplaced. Find the probability of randomly choosing two fashion magazines.

1 answer:

LekaFEV [45]3 years ago

6 0

2/22 to simplify 1/11 not sure though but I think that’s the answer u can double check though

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Skate Land charges a $50 flat fee for birthday party rental and $5.50 for each person. Joann has no more than $100 to spend on t

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9 people because you subtract 50 from 100 then divide 50 divided bt 5.50. its not a flat out number so you have to round down to 9.

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How many solutions does the system of equations have?

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no solution

Step-by-step explanation:

a solution would mean a point where the two lines cross. theres no such thing for parallel lines.

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3 years ago

Se vendieron un total de 297 boletos para la obra de teatro escolar. Los boletos eran o de adulto o de estudiante. El número de

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Answer: x boletos de adulto

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3 years ago

In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

4 0

3 years ago