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3 years ago

Explain why hexadecimal is used by computer scientists

1 answer:

3 0

Hexadecimal numerals are widely used by computer system designers and programmers. As each hexadecimal digit represents four binary digits (bits), it allows a more human-friendly representation of binary-coded values. Onehexadecimal digit represents a nibble (4 bits), which is half of an octet or byte (8 bits).

" The main reason why we use hexadecimal numbers is because it is much easier to express binary number representations in hex than it is in any other base number system." - http://digiassn.blogspot.com/2006/02/why-do-we-use-hexadecimal.html

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What percentage is 285 feet of an acre

Aleksandr-060686 [28]

Since there are 43560 feet in an acre, 285 feet is 0.654% of an acre.
Hope this helps!

6 0

3 years ago

Read 2 more answers

find the measure of the indicated angle that makes lines u and v parallel. (i will mark brain liest, please help.)

Lelu [443]

Answers:
1. 130
3. 66
5. 90
7. 53

7 0

3 years ago

Evaluate the expression Sin(tan^ -1) 34/19

lawyer [7]

Answer:

.87 I think

Step-by-step explanation:

I believe you have to evaluate the inverse tangent first then do the sine.

tan^-1 34/19 is about 1.06

sin 1.06 is about .87

3 0

3 years ago

The region in the first quadrant bounded by the x-axis, the line x = ln(π), and the curve y = sin(e^x) is rotated about the x-ax

charle [14.2K]

First, it would be good to know that the area bounded by the curve and the x-axis is convergent to begin with.

$\displaystyle\int_{-\infty}^{\ln\pi}\sin(e^x)\,\mathrm dx$

Let $u=e^x$ , so that $\mathrm dx=\dfrac{\mathrm du}u$ , and the integral is equivalent to

$\displaystyle\int_{u=0}^{u=\pi}\frac{\sin u}u\,\mathrm du$

The integrand is continuous everywhere except $u=0$ , but that's okay because we have $\lim\limits_{u\to0^+}\frac{\sin u}u=1$ . This means the integral is convergent - great! (Moreover, there's a special function designed to handle this sort of integral, aptly named the "sine integral function".)

Now, to compute the volume. Via the disk method, we have a volume given by the integral

$\displaystyle\pi\int_{-\infty}^{\ln\pi}\sin^2(e^x)\,\mathrm dx$

By the same substitution as before, we can write this as

$\displaystyle\pi\int_0^\pi\frac{\sin^2u}u\,\mathrm du$

The half-angle identity for sine allows us to rewrite as

$\displaystyle\pi\int_0^\pi\frac{1-\cos2u}{2u}\,\mathrm du$

and replacing $v=2u$ , $\dfrac{\mathrm dv}2=\mathrm du$ , we have

$\displaystyle\frac\pi2\int_0^{2\pi}\frac{1-\cos v}v\,\mathrm dv$

Like the previous, this require a special function in order to express it in a closed form. You would find that its value is

$\dfrac\pi2(\gamma-\mbox{Ci}(2\pi)+\ln(2\pi))$

where $\gamma$ is the Euler-Mascheroni constant and $\mbox{Ci}$ denotes the cosine integral function.

5 0

3 years ago

Help please i need it asap

Levart [38]

The correct answer would be 6

8 0

3 years ago