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cupoosta [38]
3 years ago
10

The expression (3x²+x+8) + (x?- 9) is equivalent to?

Mathematics
1 answer:
Andrei [34K]3 years ago
8 0

Answer: 3x^2+2x-1

Step-by-step explanation:

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Making use of the fact hat eq. (6.20) is an exact differential expression, show that what is the result of application of this e
nevsk [136]
Since there is no figure attached, I will describe the derivation of the ideal gas law. The combined gas law has no official founder; it is simply the incorporation of the three laws that was discovered. The combined gas law is a gas law that combines Gay-Lussac’s Law, Boyle’s Law and Charle’s Law.  Boyle’s law states that pressure is inversely proportional with volume at constant temperature. Charle’s law states that volume is directly proportional with temperature at constant pressure. And Gay-Lussac’s law shows that pressure is directly proportional with temperature at constant volume. The combination of these laws known now as combined gas law gives the ratio between the product of pressure-volume and the temperature of the system is constant. Which gives PV/T=k(constant). When comparing a substance under different conditions, the combined gas law becomes P1V1/T1 = P2V2/T2.
6 0
3 years ago
For which of the following conditions will the sum of integers m and n always be an odd integer?
lisov135 [29]

Answer:

option K cuz

Step-by-step explanation:

if we take m=7 and n=2

7 + 2= 9

and 9 is an odd number

5 0
3 years ago
Read 2 more answers
If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?
Keith_Richards [23]
\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}

so, the domain is all real numbers EXCEPT that one.
4 0
3 years ago
W(x) = −3x− 4; Find w(7)
Arturiano [62]

Step-by-step explanation:

Given

w(x) = - 3x - 4

Now

w(7) = - 3 * 7 - 4

= - 21 - 4

= - 25

Hope it will help :)❤

4 0
3 years ago
Which point is collinear with points a and d
Art [367]
B. (6, -8)

First, you need to figure out the slope of the line

(y1 - y2) / (x1 - x2)

After substituting points D(-3, 4) A(3, -4)

[4 - (-4)] / (-3 - 3)
(8) / (-6)

The slope of the line is -8/6 or -4/3 simplified

Then you can put it in point slope form:

(y - y1) = m(x - x1)

(y - y1) = -4/3(x - x1)

The point that I am using for point slope form is A(3, -4)

[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)

Next you have to simplify the equation so that y is isolated

y + 4 = -4/3(x - 3)

First distribute the -4/3

y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4

Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x

Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal

For example) (6, -8)
-8 = -4/3(6)
-8 = -8

So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D

~~hope this helps~~

6 0
4 years ago
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