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shusha [124]
2 years ago
8

The present value of $100 to be received 10 years from today, assuming an opportunity cost of 9 percent, is

Mathematics
1 answer:
Alona [7]2 years ago
7 0

An opportunity cost of 9 percent, is $42.

We have given that,

The present value of $100 is to be received 10 years from today,

assuming an opportunity cost of 9 percent,

present value =$100

N=10 years

I/y=9

<h3>What is the formula for the present value?</h3>

PV= FV/(1+r)^n

Where FV is the future value.

Use the given values in the formula we get,

Therefore the correct answer is 42.

To learn more about the present value visit:

brainly.com/question/20813161

#SPJ1

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If the side length is 6. cm, then the area is ______cm2 ?
ArbitrLikvidat [17]

Answer:

36 cm2

Step-by-step explanation:

tep-by-Step:

Start with the formula:

Area = a2

Don't forget: a2 = a × a (a squared).

Substitute the side length into the formula. In our example, a = 6.

Area = 6^2 = 6 × 6 = 36 cm2

Answer:

The area of the square with sides of length 6 cm is 36 cm2.

8 0
3 years ago
An iPod sold for $300, which was 200% of the actual cost. What was the actual cost?
fgiga [73]

Answer:

If $300 is 200%, half of that would be 100%. Thus, $150 is the correct answer.

Step-by-step explanation:

3 0
3 years ago
The ratio of boys to girls in a school is 4:5. How many boys are in the school if there are 720 students.
scZoUnD [109]

Answer: 320 boys

Step-by-step explanation: you would first take the total number (720) and divide it by the total number shown in the ratio (5+4=9)

720/9= 80

You would then take 80 and multiply it by 4 because that is the number representing the boys

80*4= 320

7 0
3 years ago
Please help me with this math problem, urgent please
Lady bird [3.3K]

Answer:

(X+2)(v-5)

Step-by-step explanation:

first, group and factor out the greatest common factor and combine to get (x+2)(v-5)

4 0
3 years ago
What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
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