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shusha [124]
1 year ago
8

The present value of $100 to be received 10 years from today, assuming an opportunity cost of 9 percent, is

Mathematics
1 answer:
Alona [7]1 year ago
7 0

An opportunity cost of 9 percent, is $42.

We have given that,

The present value of $100 is to be received 10 years from today,

assuming an opportunity cost of 9 percent,

present value =$100

N=10 years

I/y=9

<h3>What is the formula for the present value?</h3>

PV= FV/(1+r)^n

Where FV is the future value.

Use the given values in the formula we get,

Therefore the correct answer is 42.

To learn more about the present value visit:

brainly.com/question/20813161

#SPJ1

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The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What
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Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that \mu = 64.4, \sigma = 2.91

Sample of 50 women

This means that n = 50, s = \frac{2.91}{\sqrt{50}}

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}

Z = 1.46

Z = 1.46 has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

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If P(A)=0.54 then what value of P(B) the event A and B are complementary event
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Answer:

<em>P(B) = 0.46</em>

Step-by-step explanation:

<u>Probability</u>

The complementary event of a given event A is defined as "not A" or the event that A does not occur.

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