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Consider rectangular box with
- length x units (x≥0);
- width 3 units;
- height (8-x) units (8-x≥0, then x≤8).
The volume of the rectangular box can be calculated as
In your case,
Note that maximal possible value of the height can be 8 units (when x=0 - minimal possible length) and the minimal possible height can be 0 units (when x=8 - maximal possible length).
From the attached graph you can see that the greatest x-intercept is x=8, then the height will be minimal and lenght will be maximal.
Then the volume will be V=0 (minimal).
Answer: correct choices are B (the maximum possible length), C (the minimum possible height)
To transform the function 
to have the amplitude of 3, we need to multiply the constant 3 to the function f(x), so we have 
To transform the function
to have the midline 
we need to subtract 
by 4, so we have 
,
To transform the function to have period of 
, we need to divide the original period 
by 4, so we have 
. Note that it is the 
gives the effect of dividing the points on x-axes by 4 and the period is read on x-axes
Hence, the full transformation is given
which is the last option
To transform the function
To transform the function
Hence, the full transformation is given