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Viefleur [7K]
3 years ago
7

An astronaut who weighs 95 kilograms on Earth weighs 15.8 kilograms on the Moon. How much would a person weigh on the Moon if th

ey weigh 105 kilograms on Earth? Round your answer to the nearest tenth, or one decimal place.
please help me ​
Mathematics
1 answer:
shutvik [7]3 years ago
8 0
I do not know but u should pay more respect
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PLEASE HELP ILL VOTE
Ksju [112]

Answer:

213

Step-by-step explanation:

213

213

123

21312

3213

3 0
2 years ago
Read 2 more answers
The probability distribution for a
Tpy6a [65]

Answer:

P(x \le -3) =0.30

Step-by-step explanation:

Given

The attached probability distribution of x

Required

Find P(x \le -3)

To do this, we consider all values of x less than or equal to-3.

So, we have:

P(x \le -3) =P(x=-5) + P(x = -3)

From the table:

P(x=-5) = 0.17

P(x = -3) = 0.13

So, the equation becomes

P(x \le -3) =P(x=-5) + P(x = -3)

P(x \le -3) =0.17 + 0.13

P(x \le -3) =0.30

3 0
3 years ago
Porsha calculates the amount of money she will have at the end of 6 years on a $5,000 investment earning 3.75% interest compound
OLEGan [10]
Porsha` s expression:
5,000 ( 1 + 0.0375 ) ^24
A = P * ( 1 + i  ) ^n
n = 6 * 4 = 24
i = 0.0375 : 4 = 0.009375
Porsha`s expression is wrong. True expression is:
5,000 * ( 1 + 0.009375 ) ^24
Answer: B ) Porsha`s expression should have 1 + 0.009375 in the parentheses.

5 0
3 years ago
Read 2 more answers
Does 6(3-5w)=5(4-2w)-20w have one solution, no solution, or infinitely many solutions?
dem82 [27]

Answer:

infinite

Step-by-step explanation:

trust me I would know im a smart man in college

7 0
3 years ago
Select whether each system of equations has no solution, one solution, or infinitely many solutions.
erik [133]

Answer:

one solution, no solution, infinitely many solutions

Step-by-step explanation:

I rearranged the first equation into x=6-2y

plug that into the second equation

2(6-2y)-3y=26

12-4y-3y=26

12-7y=26

-7y=14

y=-2

Then you plug that into one of the equations

x+2(-2)=6

x-4=6

x=10

The solution to the first system is (10,-2)

the second system already has one equation as something equal to a single variable so you just plug that into the other one

4x-2(2x-4)=-6

4x -4x +8 =-6

8=-6

this is a false statement so the system of equation has no solution

Lastly I rearranged the first equation into y=2x-4 and then plug that in

6x-3(2x-4)=12

6x-6x+12=12

12=12

this statement is true so the system of equations has infinite solutions

5 0
3 years ago
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