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aliina [53]
3 years ago
7

Simplify. (-4)2 · 2 + 3 - 5 · 3

Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0

your answer is -42. you get -6 for the first part. then you multiply that by 2 to get -12, then you add 3 to get -9 then you have to subtact 5, which will bring you to -14 and -14×3 thats -42

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True or false the number 23 is a multiple of 3 because it ends in a 3
lisabon 2012 [21]

answer

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Read 2 more answers
Which values are in the solution set of the compound inequality? Select two options
zhannawk [14.2K]

The values are in the solution set of the compound inequality are (-6, -3), (3, 8).

<h3>What is inequality?</h3>

Inequality is the phenomenon of unequal distribution of resources and opportunities among the given function.

To find the number that are solutions to the compound inequalities, the value of x is

First inequality:

4(x +3) ≤0

4x +12 ≤0

4x ≤-12

x ≤-3

The value of x lies in the interval = (-∞ , -3]

Second inequality:

x +1 >3

x>2

The value of x lies in the interval = (2 , ∞)

So, the interval solution is (-∞ , -3] U (2 , ∞)

Thus, the values are in the solution set of the compound inequality are (-6, -3), (3, 8).

Learn more about inequality.

brainly.com/question/20383699

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7 0
2 years ago
a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

E = 6500 - 1500

E = 5000

<em>Hence, there are 5000kwh left after 30 days</em>

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