Answer:
Given
f(x)=18,000(.88)^x
We need to find the value of x when f(x) <2000
2000 = 18000(0.88)^x
0.88^x 2000/18000
0.88^x 1/9
• x = log (1/9) / log (0.88)
• x= 17 (rounded down)
After 17 years or during year 18 the car value will drop below $2000
Step-by-step explanation:
A=5(8)+5(8)
A=40+40
A=80in^2
![\sqrt[8]{197^{7} }](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7B197%5E%7B7%7D%20%7D)
