Evaluate: x^2b(b+x) , if x=−3 and b=2
1 answer:
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Answer:
sinA = h/c; sinC = h/a
Step-by-step explanation:
Which pair of equations below is a result of constructing the altitude, h, in Triangle ABC?
sinA= h/c
sinC= h/a
sinA= h/c
sinB= b/c
sinA= b/c
sinC= b/a
Solution:
A triangle is a polygon with three sides and three angles. There are different types of triangles such as right angled, acute, obtuse and isosceles triangle.
In right angle triangle, one angle is 90°. From Pythagoras theorem, the square of the longest side (hypotenuse) is equal to the sum of the square of the two sides.
In right triangle, trigonometric identities are used to show the relationship between the sides of a triangle and the angles.
sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse, tanθ = opposite / adjacent
Therefore in triangle ABC:
sinA = h/c; sinC = h/a
we know that
domain is all possible values of x for which any function is defined
so, here domain will be all possible values of x fro which y is defined
so, we will find minimum and maximum value of x
we can see that
x starts from 0
so, minimum value is x=0
and it goes to right upto infinity
so, domain will be
...............Answer