Answer:
4000 people id.k any other method
Step-by-step explanation:
55% = men
100-55=45
45% = 1800 (not men)
divide both by 45
1% = 40
times both by 55
55% = 2200 men
2200 + 1800 = 4000
Let
be the set of all students in the <u>c</u>lassroom.
Let
and
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given




i. We can split up
into subsets of students that pass both physics and math
and those that pass only physics
. These sets are disjoint, so

ii. 9 students fails both subjects, so we find

By the inclusion/exclusion principle,

Using the result from part (i), we have

and so the probability of selecting a student from this set is

Step-by-step explanation:
4. not enough information
5.SAS
.we have PE congruent to ER
.angle PEF congruent to angle FER
.and EF that is common for both of triangles
6.SSS
.MO congruent to KL
.MK congruent to OL
.KO that is common for both of triangles.
I think the answer is (-2,2)
Answer:
first, u need to know the formula for compound interest, which is:

where A is the final amount
P- initial amount
r- percent compounded(interest)
and
n- number of years
so
we have

3.8/100 = 0.038
1+0.038 =1.038
1.038^4 = 1.160885573136
475 * 1.160885573136 = 551.4206472396
approximately $551.42