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Mathematics

1 answer:

vladimir1956 [14]3 years ago

3 0

Answer:

Step-by-step explanation:

b i hope thate helps

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Let f(x)=x2−16x+71 .what is the vertex form of f(x)?what is the minimum value of f(x)? enter your answers in the boxes.

adell [148]

Your vertex is (8,7)

First find the x intercept
-2/2a

X = 16/2
X = 8

Substitute the value x and solve for y
Youd get 7

Hence
(8,7)

7 0

3 years ago

Read 2 more answers

Solve for x. Round to the nearest tenth, if necessary.

e-lub [12.9K]

Answer:

$\boxed {\boxed {\sf x \approx 1.9}}$

Step-by-step explanation:

We are asked to find x, a missing side in a triangle.

This is a right triangle because there is a small square in the corner representing a 90 degree or right angle. Therefore, we can use right triangle trigonometry. The three main functions are:

sinθ= opposite/hypotenuse
cosθ= adjacent/hypotenuse
tanθ= opposite/adjacent

Examine the triangle. We will use angle S, measuring 54 degrees, for theta. Side QR, measuring x, is opposite angle S. Side QS, measuring 2.3, is the hypotenuse because it is opposite the right angle. Since we have the opposite and hypotenuse, we will use sine.

$sin \theta = \frac {opposite}{hypotenuse}$

θ= 54
opposite= x
hypotenuse = 2.3

$sin (54)= \frac{ x}{2.3}$

We are solving for x, so we must isolate the variable. It is being divided by 2.3 The inverse operation of division is multiplication, so we multiply both sides by 2.3

$2.3* sin (54)= \frac{x}{2.3}*2.3$