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Zarrin [17]
2 years ago
6

Help please!!!! HURRY

Mathematics
1 answer:
damaskus [11]2 years ago
3 0

Answer:

11

Step-by-step explanation:

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Simplify negative 4 over 5 ÷ 3 over negative 2.
aliina [53]

Answer:

-4/5÷3/-2

-4/5x-2/3

8/15

8 over 15

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3 years ago
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Find the measure of angle Y. Round your answer to the nearest hundredth. (Please type the numerical answer only)
Sati [7]

Answer:

y = 11.54°

Step-by-step explanation:

Reference angle = y°

Opposite side length = 4

Hypotenuse = 20

Apply trigonometric function SOH:

Sin(y) = \frac{Opp}{Hyp}

Sin(y) = \frac{4}{20}

Sin(y) = 0.2

y = Sin^{-1}(0.2)

y = 11.536959° ≈ 11.54° (nearest hundredth)

4 0
3 years ago
Please answer each one. <br><br><br> Disclaimer: don't do it for points
Gre4nikov [31]

Answer:

for question 1 the answer is 1.5 cm  

for question 2 the answer is 0.75 cm  

for question 3 the answer is 2.3 inches  

for question 4 the answer is 3.3 inches  

for question 5 the answer is 4 cm  

for question 6 the answer is 0.75 inches

7 0
3 years ago
T=3n-1 what is the 6th term
3241004551 [841]
Plug in 1 for n and solve, then plug in 2, and so on until you get to 3(6)-1=17
6 0
3 years ago
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X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
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