I'm assuming that's a sin²(x), and not a sin(2x), right?
First, collect the terms.
7sin²(x) - 14sin(x) + 7 = 0
Factorise the quadratic.
Due to the high numbers, I'm going to use the quadratic formula to factorise the quadratic.
(-b ± √(b² - 4ac)) / 2a
Therefore
sin(x) = 1
(for both negative and positive of the quadratic formula)
Refer to the quadrant diagram.
sin(x) is a positive, meaning our answer will be on the first and second quadrant.
x = arcsin(1) = 90°
Since you don't provide an interval in your question, I'm going to assume that the interval is 0° ≤ θ ≤ 360°.
Referring again to the quadrant diagram, the solutions are going to be:
<span>θ = </span>90°, 180°
Answer: second option.
Step-by-step explanation:
In order to solve this exercise, it is necessary to remember the following properties of logarithms:
In this case you have the following inequality:
So you need to solve for the variable "x".
The steps to do it are below:
1. You need to apply to both sides of the inequality:
2. Now you must apply the properties shown before:
3. Then, rounding to the nearest ten-thousandth, you get:
Answer:
1.) Is an <em>acute</em> angle
2.)Also an <em>acute </em>angle (But at a 25 degree angle)
Step-by-step explanation:
Remember that the sum of ALL triangles' corners is 190 degrees. So just ad them up to get the degree.
Right angle = 90
Acute = < 90
Obtuse= > 90
<em>(Scalene is a type of triangle)</em>
Answer:
76%
Step-by-step explanation:
do the amount of correct answers divided by the total of questions asked.