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nataly862011 [7]

2 years ago

5

A technology research group recently published a report on computer programmers’ views about a game development program. The rep

ort noted that 54% of all programmers surveyed felt that graphics tools were easy to use.
Which factor is most relevant when evaluating the report?

A.
62% of the respondents attended public universities.
B.
80% of the respondents were between 25 and 35 years old.
C.
15% of the respondents were able to work from home.
D.
28% of the respondents worked for game development companies.

2 answers:

sergiy2304 [10]2 years ago

5 0

Answer:

A.

62% of the respondents attended public universities.

Step-by-step explanation:

Vilka [71]2 years ago

4 0

Answer:

Here you go!! Edmentum

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Which of the following situations forms a proportional relationship? Select all that apply.

Schach [20]

Answer: 1st,2nd, and 4th one are correct.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

2 years ago

Help please asap!!<br> A- z=15<br> B- z= 20<br> C- z=23<br> D- z=41

grigory [225]

Answer:

z = 15

Step-by-step explanation:

The sum S of the interior angles of a regular polygon is given by the formula

S = (n-2) x 180 where n is the number sides

Here n = 9

So S = (9-2) x 180 = 7 x 180 = 1,260

There are 9 interior angles and each angle is (5z + 65)

So the sum of all 9 interior angles = 9 (5z + 65)

= 45z + 585

Set these equal to each other and solve for z

45z + 585 = 1260

45z = 675

z = 675/45 = 15

4 0

8 months ago

If h(x) = 3 + 2f(x) , where f(1) = 3 and f '(1) = 4, find h'(1).

Leviafan [203]

H'(x) = 2f'(x)

h'(1) = 2*f'(1) = 2*4
h'(1) = 8

3 0

3 years ago

When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the <em>future value FV.</em>

In order to see the rule of formation, let's see the value (in $) for the first few years

<u>End of year 0</u>

1,000

<u>End of year 1(capital + interest + new deposit)</u>

1,000*(1.09)+10

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

<u>End of year 3 (capital + interest + new deposit)</u>

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The <em>present value PV</em> is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

2 years ago