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3 years ago

Lines C and d are perpendicular. If the slope of line c is -4, what is the slope of line d?

Mathematics

1 answer:

CaHeK987 [17]3 years ago

6 0

The slope of line D is also -4 because the lines are perpendicular.

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PLEASE HELP {It costs 5,700 every one sixth of an hour to build a hotel how many cents does building a hotel cost per second?}

Keith_Richards [23]

One sixth of an hour is 10 minutes.
That means it costs 5,700 every 10 minutes.

Costs 5,700 = 10 minutes

Dive 10 on both sides.

Costs 570 = 1 minute

Lets convert the minute into seconds.

Costs 570 = 60 seconds

Divide both sides by 60.

Costs 9.5 cents = 1 second

Round it off since you can't pay 9.5 cents.

Costs 10 cents = 1 second

This means that every second they pay 10 cents for the hotel. :D

8 0

3 years ago

Solve the following using Substitution method 2x – 5y = -13 3x + 4y = 15

Digiron [165]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\left. \begin{array} { l } { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2x-5y=-13, \: 3x+4y=15$

Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

$2x-5y=-13$

Add 5y to both sides of the equation.

$2x=5y-13$

Divide both sides by 2.

$x=\frac{1}{2}\left(5y-13\right) \\$

Multiply $\frac{1}{2}\\$ times 5y - 13.

$x=\frac{5}{2}y-\frac{13}{2} \\$

Substitute $\frac{5y-13}{2}\\$ for x in the other equation, 3x + 4y = 15.

$3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15 \\$

Multiply 3 times $\frac{5y-13}{2}\\$ .

$\frac{15}{2}y-\frac{39}{2}+4y=15 \\$

Add $\frac{15y}{2} \\$ to 4y.

$\frac{23}{2}y-\frac{39}{2}=15 \\$

Add $\frac{39}{2}\\$ to both sides of the equation.

$\frac{23}{2}y=\frac{69}{2} \\$

Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

Substitute 3 for y in $x=\frac{5}{2}y-\frac{13}{2}\\$ . Because the resulting equation contains only one variable, you can solve for x directly.

$x=\frac{5}{2}\times 3-\frac{13}{2} \\$

Multiply 5/2 times 3.

$x=\frac{15-13}{2} \\$

Add $-\frac{13}{2}\\$ to $\frac{15}{2}\\$ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

$\large\underline{ \underline{ \sf \: x=1 }}$

The system is now solved. The value of x & y will be 1 & 3 respectively.

$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

8 0

3 years ago

What is the value of x? Enter your answer in the box. i need to post graph

kondaur [170]

2x + 2 = 3x - 52
x = 54

4 0

3 years ago

If one angle of a triangle is 100 degrees and the other two angles are equal what is the measure of each unknown angle?

Shkiper50 [21]

Each of the 2 angles would be 40

5 0

3 years ago

From the beginning of cross country season to the end , Trisha reduced her time by 17 % , Anchara reduced hers by 4/25 , and Jua

kati45 [8]

Trisha - 17 percent
Anchara - 4/25 = 0.16 = 16 percent
Juanita - 16 - 13.3 = 2.7 2.7/16 (since 16 is the total) = 0.16875 = 16.875 percent

So Trisha reduced her time by the greatest percent (17)

8 0

3 years ago