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Ira Lisetskai [31]
3 years ago
14

The diagonals of a quadrilateral QRST intersect at P(2,3). QRST has vertices at Q(3,6) and R(-3,5). What must be the coordinates

of S and T to ensure that QRST is a parallelogram?
Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

S (1 , 0)

T (7 , 1)

Step-by-step explanation:

If QRST is a parallelogram, P is the mid point of segment QS and segment RT.

Basic formula for mid-point of segment: ((x1+x2)/2 , (y1+y2)/2)

T (x₁ , y₁)    S (x₂ , y₂)   P (2 , 3)    Q (3 , 6)   R (-3 , 5)

2 = (x₁ + (-3))/2         x₁ = 7

3 = (y₁ + 5)/2            y₁ = 1

T (7 , 1)

2 = (x₂ + 3))/2         x₂ = 1

3 = (y₂ + 6)/2           y₂ = 0

S (1 , 0)

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3 years ago
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
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Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

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where, \bar X = sample mean age of selected students = 22.4 years

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P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

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Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

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