Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).
<h3>What are the mean and the standard error for each sample?</h3>
Considering the data given:
<h3>What is the mean and the standard error for the distribution of differences?</h3>
The mean is the subtraction of the means, hence:
The standard error is the square root of the sum of the variances of each sample, hence:
<h3>What is the confidence interval?</h3>
It is given by:
We have a 95% confidence interval, hence the critical value is of z = 1.96.
Then, the bounds of the interval are given as follows:
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is
Since there are n logs in the pile, so we get
Thus, the total number of logs in the pile is 6.
They would be identical so it would be 114
Answer:
230 i think
Step-by-step explanation:
Answer:
27
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
3 - 6(z - 2)
z = -2
<u>Step 2: Evaluate</u>
- Substitute in <em>z</em>: 3 - 6(-2 - 2)
- (Parenthesis) Subtract: 3 - 6(-4)
- Multiply: 3 + 24
- Add: 27
