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spin [16.1K]
3 years ago
10

Please help me I am horrid at math!

Mathematics
1 answer:
Serga [27]3 years ago
7 0

Answer:23 inches

<h2>Step-by-step explanation:all sides equal 23 when added together</h2>
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Which of the following equations represents a line that is perpendicular to y=3x+11 and intercepts the line at the point, (-2, 5
yaroslaw [1]
If the line is perpendicular the slope is the reciprocal so it would be
Y=-1/3x
Then if the line has to go through the point (-2,5) the y-intercept must be 5 making the answer
Y=-1/3x+5
7 0
3 years ago
What is the COMMON DIFFERENCE of the following sequence: 10, 0, -10,
yulyashka [42]
10 is your common difference
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3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
Solve -6 - 4(-3) - 2 + 1 a.6 b.3 c.-3 d.-6​
Murljashka [212]

Answer:

Answer 5

Step-by-step explanation:

-6+12-2+1

=6-2+1

=5

4 0
3 years ago
If the temperature after 4.4 degree drop was -2.5 degrees Celsius what was the temperature at noon
Lostsunrise [7]

Answer:

1.9°C

Step-by-step explanation:

Let X be the temperature at noon and -2.5°C be the current temperature after the drop.

-We calculate temperature at noon as:

\bigtriangleup =t_o-t_n\\4.4=X--2.5\\\\X=4.4-2.5\\\\=1.5\textdegree C

Hence, the temperature at noon was 1.9°C

5 0
3 years ago
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