Answer:
5. 8/6x + 2
6. -4x - 2
7. y=3
Step-by-step explanation:
The answer is 0.4%. The probability that a unit end in a rework can be calculated using the following equation:
P(rework)= P(defects found) * P(defect)
= .8 * .005
= .004
= 0.4%
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Well you can just keep adding 55 =1hr until you get to 400 the same with 45
