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Tju [1.3M]
3 years ago
8

Graph f(x)=2^x−1 and g(x)=−x+5 on the same coordinate plane.

Mathematics
1 answer:
MaRussiya [10]3 years ago
7 0
The graphs intersect at x=2. That is the solution to f(x)=g(x).

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Which congruence postulate proves that the two triangles are<br> congruent?
inna [77]
The answer is SSS since both triangles have equal sides the third one has to be congruent since they share the same line
8 0
3 years ago
If I decline by 23%, what percent would be remaining?
egoroff_w [7]

Answer: 77%

Step-by-step explanation:

100-23=77

Hope it helps!

4 0
3 years ago
write and solve a real- world problem involving the multiplication of a fraction and a whole number whose product is between 10
Tomtit [17]

Answer:

Real word Problem:- Jean is working in a pizza shop. She has 60 kg of flour. She has used one-fifth of it for making pizzas. How much flour she used for making pizzas?

Solution:- Quantity of flour she has= 60 kg

The quantity she used in making pizzas=\frac{1}{5}\ of\ 60

=\frac{1}{5}\times60=12\ kg

hence, she used 12 kg of flour for making pizzas.

Here the multiplication of a fraction and a whole number =\frac{1}{5}\times60 and its answer is between 10 and 15, since 10<12<15.

4 0
3 years ago
Read 2 more answers
Joaquin is constructing the perpendicular bisector of ab. What should be his first step?
natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of \over{AB}.

Step-by-step explanation:

To construct a perpendicular for \over{AB}, we must first take a compass & take the distance of its arms wider than half the length of \over{AB}.

This is done in order to get two intersecting arcs in the top & bottom of \over{AB} so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above \over{AB}, draw a line joining these 2 points through their points of intersection. The point where it intersects \over{AB} is the middle-most point of \over{AB} & now a perpendicular bisector of \over{AB} is constructed.

\rule{150pt}{2pt}

3 0
2 years ago
1 of 3
lara31 [8.8K]

Answer:

a

n

=

2

2

n

−

1

Step-by-step explanation:

hope this helps

3 0
3 years ago
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