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3 years ago

Which graph below shows the solutions for the linear inequality v2-3x+1?

Mathematics

1 answer:

svetlana [45]3 years ago

4 0

Answer:

A. Graph D

Step-by-step explanation:

y >= -1/3x + 1

this means all the y values that are bigger (= above) than the line definition.

and because it says ">=", the line is included.

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You just received your final exam score from your teacher. At the top of the exam, it says you missed three questions and got 42

Leno4ka [110]

Answer:

below

Step-by-step explanation:

I would guess that they added 42 and 45 and then added 1 for their mistake. That might be a bit of stretch, but that is what I think

3 0

4 years ago

Read 2 more answers

Find the value of b if side a measures 8.7 cm?

Shkiper50 [21]

Answer:

The correct equation is 8.7 + b = 54.6

Step-by-step explanation:

because it is given that measure of side a is 8.7cm, in all other equations the values of a is different.

6 0

3 years ago

What is the difference between 2a + 5 and 2(a + 5)? Give an English expression to describe each of

Sergio [31]

Answer:

without brackets, the two is only multiplying the a. with brackets, you distribute the 2, making the equation 2a+10

Step-by-step explanation:

6 0

3 years ago

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

5 0

4 years ago

What is the completely factored form of this polynomial?

Sholpan [36]

Answer:

A. (x + 2)²(x - 2)²

Step-by-step explanation:

x⁴ - 8x² + 16 =

(x² - 4)(x² - 4) =

(x - 2)(x + 2)(x - 2)(x + 2) =

(x - 2)²(x + 2)²

5 0

3 years ago