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dimulka [17.4K]
3 years ago
12

I need help with this am not smart pls help

Mathematics
1 answer:
rjkz [21]3 years ago
7 0
I’ll try but I can’t promise ;(
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The perimeter of Stephanie’s triangle is half the perimeter of Juan’s triangle. Juan’s triangle is shown. Write a numerical expr
denpristay [2]

The perimeter of a triangle is the sum of all side lengths of the triangle. The numerical expression for the perimeter of Stephanie's triangle is: \frac 12 \times 25

Let the sides of Juan's triangle be x, y and z. So:

x = 5 \\ y = 8\\ z = 12

The perimeter (J) of Juan's triangle is calculated by adding all sides.

So:

J =x +y +z

This gives:

J =5 + 8 + 12

J =25

From the question, we understand that:

The perimeter (S) of Stephanie's triangle is half that of Juan.

This means that:

S = \frac 12J

Substitute 25 for J

S = \frac 12 \times 25

Hence, the numerical expression for the perimeter of Stephanie's triangle is: \frac 12 \times 25

Read more about perimeters at:

brainly.com/question/11957651

4 0
3 years ago
Read 2 more answers
For which points is the y coordinate less that -1.5
Masja [62]
The bottom 2.

I can’t see the point names cause its blurry but those bottom 2 points should be the answers.

Y coordinates are how high or low
X coordinates are how far left or right

Brainliest if this helps?
3 0
3 years ago
كيفية حساب cos a و tan a بحيث sin a يساوي 1على 2
Paraphin [41]

Answer:

uh i dont know

Step-by-step explanation:

8 1
3 years ago
HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
Solve for x. Round your answer to the nearest tenth.
Rainbow [258]

Answer:

24.8

Step-by-step explanation:

x = √(16)^2+(19)^2= 24.8

7 0
3 years ago
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