Answer:
let the numbers be, x and x+1 ( as it is consecutive number the next number will have 1 more than the number )
sum = 41
so, x + ( x + 1 ) = 41
x + x + 1 = 41
2x + 1 = 41
2x = 41 -1 = 40
2x = 40
x = 40/2 = 20
x = 20
x + 1 = 20 + 1 = 21
so the consecutive numbers whose sum is 40 are, 20 and 21
hope this answer helps you.....
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The terminal point of the circle is D
Area of the shaded region = Area <span>of a square - Area of a circle
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Side of a square = 2r
Area of a square = (2r)² = 4r²
Area of a circle = πr²
Area of the shaded region = 4r² - πr² = <span>r²(4-π)</span>
