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Angelina_Jolie [31]

3 years ago

11

PLS HELP The figure shown is created by joining two rectangles. Enter the area, in square inches, of the figure.

2 answers:

Kipish [7]3 years ago

7 0

Answer:

Its 108 because you have to split up the rectangles so when you cut them in half you will have 2 separate rectangles 1 with a base of 8 and a height of 9 so you will multiply those so 9 x 8 = 72 then just do the other two so 6 x 6 = 36 now you add those together 36 + 72 = 108 hope that helps

Ugo [173]3 years ago

4 0

The Answer Is 108

Find the top length by adding 8+6=14

And the sides are the same length, meaning the sides are equivalent to 6.

6x14=84.

To find the sides for the the other rectangle, do 9-6 to get the side 3.

3x8=24

Add both areas to get 108 Inches Squared.

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What is the solution to this system of equations? x 2 y = 4. 2 x minus 2 y = 5. (3, Negative 5 and one-half) (3, one-half) no so

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The solution of the equation is (3, 1/2).

<h2>We have to determine</h2>

What is the solution to this system of equations?

<h3>According to the question</h3>

The given system of the equation;

$\rm x+2y=4\\
\\
2x-2y=5$

<h3>The standard form for linear equations in two variables is;</h3>

$\rm Ax+By = C$

On comparing equation 1 and equation 2 with the standard form we get,

$\rm a_1 = 1,\ b_1 = 2,\ c_1=4\\
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Here,

$\rm \dfrac{a_1}{a_2} = \dfrac{1}{2}\\
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\dfrac{b_1}{b_2} = \dfrac{-2}{2} = -1\\
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\dfrac{a_1}{a_2} \neq \dfrac{b_1}{b_2}$

Here, $\rm \dfrac{a_1}{a_2} \neq \dfrac{b_1}{b_2}$ so, the given system of equations has a unique solution.

Then,

The solution of the equation is;

$\rm x+2y=4\\\\2x-2y=5$

On adding both the equation;

$\rm x+2y+2x-2y=4+5\\
\\
3x=9\\
\\
x = \dfrac{9}{3}\\
\\
x = 3$

Substitute the value of x in equation 1,

$\rm x+2y=4\\
\\
3+2y = 4\\
\\
2y = 4-3\\
\\
2y=1\\
\\
y =\dfrac{1}{2}$

Hence, the solution of the equation is (3, 1/2).

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