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Angelina_Jolie [31]
3 years ago
11

PLS HELP The figure shown is created by joining two rectangles. Enter the area, in square inches, of the figure.

Mathematics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

Its 108 because you have to split up the rectangles so when you cut them in half you will have 2 separate rectangles 1 with a base of 8 and a height of 9 so you will multiply those so 9 x 8 = 72 then just do the other two so 6 x 6 = 36 now you add those together 36 + 72 = 108 hope that helps

Ugo [173]3 years ago
4 0

The Answer Is 108

Find the top length by adding 8+6=14

And the sides are the same length, meaning the sides are equivalent to 6.

6x14=84.

To find the sides for the the other rectangle, do 9-6 to get the side 3.

3x8=24

Add both areas to get 108 Inches Squared.

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Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
3 years ago
How do I find x in this problem?
torisob [31]

Answer:

(6-2)×180 = 720

101+154+72+123+145+x=720

595 + x = 720

x = 720-595

x= 125

5 0
3 years ago
Express the illuminance on the floor as a composite function of t for 0 &lt; t &lt; 8.
GrogVix [38]
The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t

The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²

The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
3 0
3 years ago
What are the answer for your these questions?
ozzi

Answer:

<u>a. 11</u>

<u>b. 9</u>

Step-by-step explanation:

<em>A:</em>

2 x 4 = 8

8 + 3 = 11

<em>B:</em>

-2 x -2 = 4

4 + 5 = 9

Hope this helps! Let me know if it was right!

5 0
3 years ago
Which statements are true about the interquartile range? Select all that apply.
PilotLPTM [1.2K]

Answer:

The true statements are:

B. Interquartile ranges are not significantly impacted by outliers

C. Lower and upper quartiles are needed to find the interquartile range

E. The data values should be listed in order before trying to find the interquartile range

Step-by-step explanation:

The interquartile range is the difference between the first and third quartiles

Steps to find the interquartile range:

  • Put the numbers in order
  • Find the median Place parentheses around the numbers before and after the median
  • Find Q1 and Q3 which are the medians of the data before and after the median of all data
  • Subtract Q1 from Q3 to find the interquartile range

The interquartile range is not sensitive to outliers

Now let us find the true statements

A. Subtract the lowest and highest values to find the interquartile range ⇒ NOT true (<em>because the interquartial range is the difference between the lower and upper quartiles</em>)

B. Interquartile ranges are not significantly impacted by outliers ⇒ True <em>(because it does not depends on the smallest and largest data)</em>

<em />

C. Lower and upper quartiles are needed to find the interquartile range ⇒ True <em>(because IQR = Q3 - Q2)</em>

<em />

D. A small interquartile range means the data is spread far away from the median ⇒ NOT true (<em>because a small interquartile means data is not spread far away from the median</em>)

E. The data values should be listed in order before trying to find the interquartile range  ⇒ True <em>(because we can find the interquartial range by finding the values of the upper and lower quartiles)</em>

4 0
3 years ago
Read 2 more answers
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