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baherus [9]
2 years ago
7

Find the area of the circle. Use 3.14 or 22/7 for pi. Round your answer to the nearest hundredth, if necessary.

Mathematics
1 answer:
Minchanka [31]2 years ago
3 0
3.14 . 16
= 50,24
good luckkkkkkk
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The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a
AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

<u><em>Let X = time for this event for boys in secondary school</em></u>

SO, X ~ Normal(\mu=460,\sigma^{2} =40^{2})

The z-score probability distribution for normal distribution is given by;

                               Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean time = 460 seconds

            \sigma = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;</u>

       P(X > x) = 0.10   {where x is the required time which boy need to beat}

       P( \frac{X-\mu}{\sigma} > \frac{x-460}{40} ) = 0.10

        P(Z > \frac{x-460}{40} ) = 0.10

<em>So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;</em>

<em>                   </em>      \frac{x-460}{40} =1.2816

                         {x-460}{} =1.2816\times 40

<em>                           </em>x = 460 + 51.264 = <u>511.264 seconds</u>

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

8 0
3 years ago
I need help with this equation 5x (2x-2)
Doss [256]
Answer: 10x^2-10x

Explanation: You would distribute the 5x into the parenthesis making it 10x(to the second power) -10x
8 0
3 years ago
Michael can type 4 pages of his term paper in 30 minutes. How long will it take him to type the paper if it has 14 pages?
Stella [2.4K]

Answer:

105 minutes

Step-by-step explanation:

we know that

Michael can type 4 pages of his term paper in 30 minutes

so

using proportion

Find out how long will it take him to type the paper if it has 14 pages

\frac{30}{4}\frac{min}{pages}=\frac{x}{14}\frac{min}{pages}\\\\x=30*14/4\\ \\x=105\ min

8 0
3 years ago
I really need help with 15 and 16 please
Mandarinka [93]

Answer:

  15. 50 kg

  16a. 5 kg

  16b. 3.75 kg

Step-by-step explanation:

The formula relating force, mass, and acceleration can be solved for mass. This formula will apply to both problems. We'll use m for both "mass" and "meters". We presume you can avoid getting mixed up by understanding that meters is used in the context of acceleration: m/s².

  F = ma

  m = F/a . . . . . divide by a

__

15. m = (250 N)/(5 m/s²) = 50 kg

__

16a. m = (15 N)/(3 m/s²) = 5 kg

16b. m = (15 N)/(4 m/s²) = 3.75 kg

_____

<em>Comment on units</em>

Especially for physics problems, I like to keep the units with the numbers. It is helpful to remember that Newtons are equivalent to kg·m/s². So, dividing Newtons by acceleration in m/s² will give mass in kg. Since you're familiar with F=ma, it's not too hard to remember that the units of force (N) are the product of the units of mass (kg) and acceleration (m/s²).

6 0
3 years ago
A company lost an average of $30,000 per month. Find the total loss of the company in 1 year.
Art [367]

Answer:

$360,000

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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