Step 1: Find the area of the bases (triangles)
A = 1/2 * base * height
A = 1/2 * 16 * 6
A = 48
48 + 48 = 96
Area of the triangles = 96 cm^2
Step 2: Find the area of the sides (rectangles)
A = base * height
A1 = 16 * 12
A1 = 192
A2 = 10 * 12
A2 = 120
120 + 120 = 240
240 + 192 = 432 cm^2
Step 2: Add the areas together
96 + 432
528 cm^2
Hope this helps!! :)
Use pythagoras
d = √(Δx² + Δy²)
d = √(12-2)² + (9-4)²
d = √(10² + 5²)
d = √(100 + 25)
d = √125
d = 5√5
d = 5 × 2.236
d = 11.18
The nearest tenth is 11.2, so the distance is near to 11.2
Answer:
C, 15
Step-by-step explanation:
i looked it up