1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vagabundo [1.1K]
2 years ago
13

ONE of Michael's birds came out of the cage and flew away.

Mathematics
1 answer:
Julli [10]2 years ago
5 0

Answer:

100.0 bc it is ONE bird or 100%?????

You might be interested in
From $90 to $39.<br> What is the percent of change? (round to nearest WHOLE percent)
DENIUS [597]
The percentage would be 51% but if you want to round it the answer is 50%
7 0
3 years ago
Read 2 more answers
Costs are rising for all kinds of medical care. The mean monthly rent at assisted-living facilities was reported to have increas
polet [3.4K]

Answer:

a) The 90% confidence interval estimate of the population mean monthly rent is ($3387.63, $3584.37).

b) The 95% confidence interval estimate of the population mean monthly rent is ($3368.5, $3603.5).

c) The 99% confidence interval estimate of the population mean monthly rent is ($3330.66, $3641.34).

d) The confidence level is how sure we are that the interval contains the mean. So, the higher the confidence level, more sure we are that the interval contains the mean. So, as the confidence level is increased, the width of the interval increases, which is reasonable.

Step-by-step explanation:

a) Develop a 90% confidence interval estimate of the population mean monthly rent.

Our sample size is 120.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 120-1 = 119

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.90}{2} = \frac{0.10}{2} = 0.05

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 119 and 0.05 in the t-distribution table, we have T = 1.6578.

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{650}{\sqrt{120}} = 59.34

Now, we multiply T and s

M = T*s = 59.34*1.6578 = 98.37

The lower end of the interval is the mean subtracted by M. So it is 3486 - 98.37 = $3387.63.

The upper end of the interval is the mean added to M. So it is 3486 + 98.37 = $3584.37.

The 90% confidence interval estimate of the population mean monthly rent is ($3387.63, $3584.37).

b) Develop a 95% confidence interval estimate of the population mean monthly rent.

Now we have that \alpha = 0.95

So

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

With 119 and 0.025 in the t-distribution table, we have T = 1.9801.

M = T*s = 59.34*1.9801 = 117.50

The lower end of the interval is the mean subtracted by M. So it is 3486 - 117.50 = $3368.5.

The upper end of the interval is the mean added to M. So it is 3486 + 117.50 = $3603.5.

The 95% confidence interval estimate of the population mean monthly rent is ($3368.5, $3603.5).

c) Develop a 99% confidence interval estimate of the population mean monthly rent.

Now we have that \alpha = 0.99

So

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.005

With 119 and 0.025 in the t-distribution table, we have T = 2.6178.

M = T*s = 59.34*2.6178 = 155.34

The lower end of the interval is the mean subtracted by M. So it is 3486 - 155.34 = $3330.66.

The upper end of the interval is the mean added to M. So it is 3486 + 155.34 = $3641.34.

The 99% confidence interval estimate of the population mean monthly rent is ($3330.66, $3641.34).

d) What happens to the width of the confidence interval as the confidence level is increased? Does this seem reasonable? Explain.

The confidence level is how sure we are that the interval contains the mean. So, the higher the confidence level, more sure we are that the interval contains the mean. So, as the confidence level is increased, the width of the interval increases, which is reasonable.

4 0
3 years ago
Marlon asks a friend to think of a number from 5 to 11. What is the probability that Marlon’s friend will think of the number 9?
Strike441 [17]

Answer:

1/7

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
In this hanger, the weight of the triangle is x and the weight of the square is y.
Sedbober [7]

Answer:

y = 4

Step-by-step explanation:

4y 1x  

3x 1y

1x=6

18

6+16 =22

18+4= 22

4 0
2 years ago
Bart and Sam played a game in which each player earns turn.A players total score after two turns is the sum of his points earned
Svetradugi [14.3K]
Bart earned 123 pts and lost 180
123-180=-57
Sam earned 185 pts and lost 255
185-225=-70
Bart won because he had -57 pts and Sam had -70
8 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the following are identities? Check all that apply
    7·2 answers
  • The panda at those who became ill and lost 4 pounds every week for five weeks in the 6th week she began to feel better and gaine
    8·1 answer
  • Which equation represents the line that passes through the points (-1,-2) and (3,10)?a.y = 3x + 1b.y = 3x - 1c.y = 4x + 2d.y = 4
    9·1 answer
  • Factorize x^3-2x^2-13x-10
    11·1 answer
  • Using the number 686293, what is the value of the digit 8
    5·1 answer
  • Complete the two-column proof.
    9·1 answer
  • (x)=7x-3 and g(x)=x^2-4,find (f+g)(x)
    14·1 answer
  • Please help I need help with my hw
    15·1 answer
  • Earl needs to fill juice cups for his little brothers birthday party. There are 25 juice cups and each juice cup holds 12 fluid
    12·2 answers
  • There are 380 female students in a class. Male students make up 60% of the class. What is the total number of students in the cl
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!