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aalyn [17]
2 years ago
12

Simplify 3x + 6x2 - 5x - x2 6x2 + 2x 0 6x²-2x 5x2 - 2x 5x2 + 2x HELP

Mathematics
2 answers:
mel-nik [20]2 years ago
6 0
The correct answer I got was 5x^2 - 2x. So it’s the 3rd one. Hope this helps
nydimaria [60]2 years ago
3 0

Step-by-step explanation:

I don't get it can post a picture with it so I can understand more better then the writing

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Step-by-step explanation:

- 7 \frac{1}{10}   \div   \frac{2}{5}

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=  -  \frac{71}{2}  \times  \frac{1}{2}

=  -  \frac{71}{4}

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3 0
3 years ago
Jennifer utilizo 2/7 de metro de cinta para hacer moños para sus primas. Ahora le quedan 10/21 de metro de cinta. ( problema ver
Vikki [24]

Answer:

x = \frac{16}{21}\,m

Step-by-step explanation:

El enunciado pregunta la cantidad inicial de cinta utilizada por Jennifer, la cual es la suma de la porción utilizada y la porción remanente:

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6 0
2 years ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
2 years ago
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