Find the distance between the two points rounding to the nearest tenth (if

Mathematics

1 answer:

lana [24]3 years ago

6 0

Answer:

5.7

Step-by-step explanation:

Creating the point into a triangle, both sides a 4.

As the Pythagorean theorem goes, a^2+b^2=c^2

4^2+4^2=

16+16=

The square root of 32 is about 5.7

The distance between the points is about 5.7 units

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What's 29.4983 rounded to the nearest cent

konstantin123 [22]

We need to identify what "the nearest cent" is.

So!
AB.CD

That is a representation of a number using variables, but we'll just say it's for place values.

A is in the Tens Place
B is in the Ones Place
C is in the Tenths Place (1/10)
D is in the Hundredths Place (1/100

Since we are talking about money let's put it in relation to a dollar.

A is in the Ten Dollar Place
B is in the One Dollar Place
C is in the Tenth of a Dollar Place (1/10 of a dollar)
D is in the Hundredth of a Dollar Place (1/100 of a dollar)

So, what is 1/10 of a dollar?
What amount of money times 10, would get you 1 dollar. Or you can think of it as if you had 10 of one value of money and you got a dollar what is that? A dime.

Now, what is 1/100 of a dollar?
What amount of money times 100, would get you 1 dollar. 1 cent (Or it is sometimes called a penny).

So that means any number beyond the 1/100 of a dollar point (D) will be rounded. If it's the first number after the 1/100 of a dollar is greater than (or equal to) 5 then we round the cent value up. If it is less than 5 we round down.

$29.4983
So, 9 is our cent place. 8 is greater than 5, so we round 9 up. (Add 1. Since it is 9 it will carry over into the 1/10 of a dollar place)

Our answer is:
$29.50

8 0

3 years ago

Describe the nature of the roots for this equation.<br> 3x^2+x-5= 0

m_a_m_a [10]

Answer:

<h2>This equation has no natural roots.</h2>

Step-by-step explanation:

$3x^2+x-5=0\\\\\text{Use the quadratic formula for}\ ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{For the given equation:}\\\\a=3,\ b=1,\ c=-5\\\\b^2-4ac=1^2-4(3)(-5)=1+60=61\\\\x=\dfrac{-1\pm\sqrt{61}}{(2)(3)}=\dfrac{-1\pm\sqrt{61}}{6}\notin\mathbb{N}$