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saul85 [17]
3 years ago
13

Find the distance between the two points rounding to the nearest tenth (if

Mathematics
1 answer:
lana [24]3 years ago
6 0

Answer:

5.7

Step-by-step explanation:

Creating the point into a triangle, both sides a 4.

As the Pythagorean theorem goes, a^2+b^2=c^2

4^2+4^2=

16+16=

32

The square root of 32 is about 5.7

The distance between the points is about 5.7 units

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Find the slope of the line through the given points (1,6),(-8,-9)
cestrela7 [59]
The answer to the question

6 0
3 years ago
If candy cost $5.99 a pound how much would it cost to buy four and a quarter pounds of candy
Degger [83]

Answer:

25.4575

Step-by-step explanation:First since one candy is 5.99 we multiply it by 4 1/4 ponds and then we get $25.4575


7 0
3 years ago
Evie and her father are comparing their ages. At the current time, Evie's father is 36 years older than her. Theee years from no
artcher [175]
Let F be the father's current age, and E be Evie's current age.
F = E + 36                 this is the current relation between the ages
F + 3 = 5(E + 3)        this the relationship in 3 year (hence the + 3)
Then solve by substituting one equation into another:
(E + 36) + 3 = 5(E + 3)
         E + 39 =  5E + 15
                24 = 4E
                  6 = E
Evie's current age is 6.
7 0
3 years ago
I will give brainlyiest <br> Evaluate the expression 5(7 − 4)︿2 ÷ 3 + 11.<br> 3<br> 14<br> 26<br> 33
bija089 [108]

Answer:

26

Step-by-step explanation:

6 0
3 years ago
A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank
harkovskaia [24]

Answer:

The value  is P_o = \$ 561958.9

Step-by-step explanation:

From the question we are told that

  The capacity of the metal  tank is  C =  2000 \  gallon

   The duration usage is  t = 15\ years \ ago

   The cost of 2000-gallon tank 15 years ago is P =  \$100,000

    The capacity of the second tank considered is C_1 = 5,000  

    The power sizing exponent is e = 0.57

     The initial construction cost index is  u_1 = 180

      The new construction after 15 years cost index is  u_2 =600

Equation for the power sizing exponent is mathematically represented as

      \frac{P_n}{P} = [\frac{C_1}{C} ]^{e}

=> Here P_n is the cost of 5,000-gallon tank as at 15 years ago  

So

     P_n  =  [\frac{5000}{2000} ] ^{0.57} * 100000

      P_n  =  \$168587.7

Equation for the cost index exponent is mathematically represented as

      \frac{P_o}{P_n}  =  \frac{u_2}{u_1}

HereP_o is the cost of 5,000-gallon tank today

So

       \frac{P_o}{168587.7}  =  \frac{600}{180}

=>    P_o = \frac{600}{180} * 168587.7

=>      P_o = \$ 561958.9

8 0
3 years ago
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