The answer:
the complement of the question proposed one of the choices given beneath:
a) 58.8
b) 53.0
c) 29.4
d) 26.5
as we observe at the figure, AOB an isosceles triangle, and OCB is a right triangle
consider OCB
OC =9, OB= radius = 28
the problem is how to find the length of CA, for that C is a midpoint of segment AB, so AC=BC
BC can be found by using pythagorean theorem
OB²= OC² + CB², this implies CB² = OB² - OC²
CB² = 28² - 9² = 784 - 81=703, therefore CB= sqrt (703)=26.51
CB=26.51, since CB= AC, so AC=CB= 26.51
finally the <span>the length of AB is AB = 2 x CB = 2x AC= 2x 26.51= 53.0
</span>
the answer is b) 53.0
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The answer to your question is 215
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Voy a responder en el mismo idioma en que está la pregunta.
1) Venta con ganancia
Precio de venta 60 soles.
Ganancia = 20% del costo => costo + 0,20 * costo = precio
=> costo (1 + 0,20) = precio = 60 soles
=> costo (1,20) = 60 soles => costo = 60 soles / 1,20 = 50 soles
2) Venta con pérdida del 20%
Pérdida = 20% del costo
=> costo - precio = 20% * costo => costo - 0,20*costo = precio
=> costo ( 1 - 0,20) = 60 soles => costo * 0,80 = 60 soles
=> costo = 60 soles / 0,80 = 75 soles
3) Costo total = 50 soles + 75 soles = 125 soles
4) Ganancia total = valor total de venta - costo total
Ganancia total = 2 * 60 soles + 125 soles = 120 soles - 125 soles = - 5 soles.
El signo negativo significa que al final se perdió 5 soles en la operación.
