Answer:
A lot can happen, depending on the use of the variable
Explanation:
Lets create a position variable, a common variable in games.
Vector3 position = new Vector3(0, 0, 0);
The above variable initialization creates a new Vector3 object. The Vector3 class contains 3 properties, X, Y, and Z. When you assign the variable 'position' the new Vector3 object, the variable 'position' contains an instance of Vector3 where
X = 0,
Y = 0,
and Z = 0.
The variable 'position' can be used to set the position of a player, or an object.
We can reuse this variable when you want the object or player to move.
position.X = 29
position.Y = -14
position.Z = 47
now the object/player's position is (29, -14, 47).
Variables can be used for basically everything you need in programming, from storing a position, to storing the result of a complex math equation.
Answer:
i not know mainframe computer there is many use of computer
The exercise is about filling in the gaps and is related to the History of the ARPANET.
<h3>
What is the History of the ARPANET?</h3>
From the text:
In 1972, earlier designers built the <u>ARPANET </u>connecting major universities. They broke communication into smaller chunks, or <u>packets </u>and sent them on a first-come, first-serve basis. The limit to the number of bytes of data that can be moved is called line capacity, or <u>bandwidth</u>.
When a network is met its capacity the user experiences <u>unwanted pauses</u>. When the network is "slowing down", what is happening is users are waiting for their packet to leave the <u>queue</u>.
To make the queues smaller, developers created <u>mixed </u>packets to move <u>simultaneously</u>.
Learn more about the ARPANET at:
brainly.com/question/16433876
Answer:
- The graph of the function is attached below.
- The x-intercepts will be: (2, 0), (-2, 0)
- The y-intercept will be: (-20, 0)
Explanation:
Given the function

As we know that the x-intercept(s) can be obtained by setting the value y=0
so

switching sides

Add 20 to both sides


Dividing both sides by 5





so the x-intercepts will be: (2, 0), (-2, 0)
we also know that the y-intercept(s) can obtained by setting the value x=0
so



so the y-intercept will be: (-20, 0)
From the attached figure, all the intercepts are labeled.