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3 years ago

3x + 2 38 12/ 12 30 12x-7

Mathematics

1 answer:

MakcuM [25]3 years ago

5 0

Answer:

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Step-by-step explanation:

5ug77hhig jk uyhvhbbijvcujgguihgguhgj

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The area of a rectangle is 60 sq. cm. The rectangle's length is 12 cm.

Lunna [17]

A= l times w
60=12w
W=5

8 0

2 years ago

Please help out with this if you can.

Pepsi [2]

Answer:

3/7 and 4/17

Step-by-step explanation:

a) given that Shen is playing a game and the probability of unlocking the treasure test is 3/10.

To find the odds in favour of his character unlocking the treasure chest.

Since probability = 3/10 we have favourable and total are in the ratio 3:10

i.e. favourable:Favourable+unfavourable= 3:3+7

Hene odds= favourable:unfavourable =3/7

Answer is 3/7

b) Given that odds against choosing a blue block are 13/4

This means there are 4 blue blocks and 13 other colour blocks.

Total blocks= 13+4 =17

No of blue blocks = 4

Probability of selecting blue block=4/17

6 0

3 years ago

What does 2+2 equal

lisabon 2012 [21]

2+2=4

a^2+b^2=c^2
15^2-4^2
=225-16
=209

4 0

3 years ago

Read 2 more answers

A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data

LuckyWell [14K]

Answer:

(25.53, 37.87): 95% CI

(23.59, 39.81): 99% CI

Step-by-step explanation:

The margin of error of a confidence interval is given by:

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

z is related to the confidence level. The higher the confidence level, the higher the values of z, and thus, we wider the confidence interval is.

In this question:

The narrower C.I. is the 95%, and the wider is the 99%. So

(25.53, 37.87): 95% CI

(23.59, 39.81): 99% CI

4 0

3 years ago

What is the inverse of cube root x/3 +1

Ostrovityanka [42]

Answer:

${f}^{ - 1} (x) = 3 {x}^{2} - 3$

Step-by-step explanation:

We want to find the inverse of

$y = \sqrt[3]{ \frac{x}{3} + 1}$

We interchange x and y to get:

$x= \sqrt[3]{ \frac{y}{3} + 1}$

We solve for y;

${x}^{2} = \frac{y}{3} + 1$

Multiply through by 3

$3 {x}^{2} = y + 3$

Subtract 1 from both sides:

$y = 3 {x}^{2} - 3$

Therefore the inverse is

${f}^{ - 1} (x) = 3 {x}^{2} - 3$

8 0

3 years ago