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Phantasy [73]
2 years ago
14

A tire shop starts off with the same number of tires every month. In January,

Mathematics
1 answer:
7nadin3 [17]2 years ago
4 0

Answer:

the answer is B

Step-by-step explanation:

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Help me plz 10 points. its only middle school work. one question.
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Answer:

98

Step-by-step explanation:

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2 years ago
Quinn and her friends were handing out flyers for their lemondare stand. There were 35 friends and they each handed out 126 flye
shutvik [7]
If Quinn is included in the 35 friends the answer would be 35x126=4410.
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3 years ago
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Find the value of x, y, and z in the rhombus below.
Yuki888 [10]

Solution:

<u>It should be noted:</u>

  • Opposite sides of a rhombus are always equal.
  • Opposite angles of a rhombus are always equal.

<u>Thus:</u>

  • (-y - 10) = 90°
  • 3z - 3 = 90°
  • 4x - 2 = 90°

<u>Finding x:</u>

  • 4x - 2 = 90°
  • => 4x = 90 + 2
  • => 4x = 92
  • => x = 23

<u>Finding y:</u>

  • (-y - 10) = 90°
  • => -y - 10 = 90°
  • => -y = 100
  • => y = -100

<u>Finding z:</u>

  • 3z - 3 = 90°
  • => 3z = 90 + 3
  • => 3z = 93
  • => z = 31
4 0
2 years ago
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Women's heights are normally distributed with a mean given by p = 63.6 in. and a standard deviation given by o = 2.5 in. (a) If
Ganezh [65]

Step-by-step explanation:

I am sorry question samajh Nahin a Raha question dijiye

4 0
3 years ago
If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?
melamori03 [73]
\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$4432.37\\&#10;P=\textit{original amount deposited}\to &\$3000\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &8&#10;\end{cases}

\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8&#10;\\\\\\&#10;\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r&#10;\\\\\\&#10;0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086&#10;\\\\\\&#10;r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}
6 0
3 years ago
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