Quadrilateral ABCD shown below, is translated 3 units to the left to create quadrilateral A'BCD
1 answer:
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The triangles formed by the path of the ball and the wall in the given diagram are similar triangles.
<h3>Correct Response;</h3>The point on the wall she should aim is; <u>A. 7.8 feet away from point B</u>
<h3 /><h3>Method by which the above value is obtained;</h3>The possible diagram in the question is attached
Let <em>x</em> represent the distance from point <em>B</em> where the ball lands.
ΔCDE is similar to ΔABE, by Angle-Angle similarity postulate.
By trigonometric ratio, the tangent of the angles ∠CDE and ∠BAE are;
tan(∠CDE) = tan(∠BAE)
Therefore;
Which gives;
16 × (20 - x) = 25·x
320 = 41·x
x = 320 ÷ 41 ≈ 7.8
The point on the wall she should aim if she's standing at point <em>A</em> is therefore;
- <u>A, 7.8 feet away from point </u><u><em>B</em></u>
Learn more about trigonometric ratios here:
