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vampirchik [111]
1 year ago
11

Equations/Dimensions

Mathematics
1 answer:
Serjik [45]1 year ago
8 0

Answer:

bjmm

Step-by-step explanation:

joy.b

vvvgj.

vvhjkgdwwryuiohb

gfuiokhhhjjkpp0oo

hbjv vhkghwv kmkoitd jhgeqru vhhdec

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The area of a playground is 256²m find the length of the playground
Sauron [17]

Answer:

I'm pretty sure the length is 16m.

Step-by-step explanation:

If the area is a total of 256^2 m, then finding the square root of that area would get you the side length of the playground. The square root of 256 is 16, therefore the sidelength of the playground is 16m :)

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3 years ago
Your parents allow you to borrow a car to get to your part-time job, but you have to pay for a tank of gas each month. Gasoline
Ahat [919]
Step one is to take 2.76 x 15.  That will give us the total cost.  That is 41.40. Next, we need to divide 41.40 by 2.  So in total, it will save you 20.70.
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Dustin bought a DVD player that was marked down from $150 to $100. A video game console was $250 and marked down by $75. Which d
Vika [28.1K]

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It would be the game console

Step-by-step explanation:

The DVD player went down $50 the console went down about $100 and that is a better idea

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Which type of angle is
lianna [129]

Answer:

huh

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wheres the angle??????

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Solve the compound inequality |3x-9|≤15 and |2x-3|≥5. Give answer in interval notation.
laila [671]

Answer:

The solution of |3x-9|≤15 is [-2;8] and the solution |2x-3|≥5 of is  (-∞,2] ∪ [8,∞)

Step-by-step explanation:

When solving absolute value inequalities, there are two cases to consider.

Case 1: The expression within the absolute value symbols is positive.

Case 2: The expression within the absolute value symbols is negative.

The solution is the intersection of the solutions of these two cases.

In other words, for any real numbers a and b,

  • if |a|> b then a>b or a<-b
  • if |a|< b then a<b or a>-b

So, being |3x-9|≤15

Solving: 3x-9 ≤ 15

3x ≤15 + 9

3x ≤24

x ≤24÷3

x≤8

or 3x-9 ≥ -15

3x ≥-15 +9

3x ≥-6

x ≥ (-6)÷3

x ≥ -2

The solution is made up of all the intervals that make the inequality true. Expressing the solution as an interval: [-2;8]

So, being |2x-3|≥5

Solving: 2x-3 ≥ 5

2x ≥ 5 + 3

2x ≥8

x ≥8÷2

x≥8

or 2x-3 ≤ -5

2x ≤-5 +3

2x ≤-2

x ≤ (-2)÷2

x ≤ -2

Expressing the solution as an interval: (-∞,2] ∪ [8,∞)

6 0
3 years ago
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