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Readme [11.4K]
3 years ago
10

A skier skis along a circular ski trail that has a radius of 1.25 km. The skiier starts at the East side of the ski trail and tr

avels in the CCW direction. Let θ θ represent the radian measure of the angle the skier has swept out. Suppose cos ( θ ) = 0.9 cos(θ)=0.9 and sin ( θ ) = 0.43 sin(θ)=0.43. What does the 0.9 in cos ( θ ) = 0.9 cos(θ)=0.9 represent in this context? Select all that apply.
A. The skiier is 0.48 radius lengths to the North of the center of the ski trail.

B. The skiier is 0.88 radius lengths to the East of the center of the ski trail.

C.The skier is 0.48 km to the North of the center ofthe ski trail.

D. The skiier is 0.88 km to the East of the center of the ski trail.
Mathematics
1 answer:
Simora [160]3 years ago
3 0
You’re answer would be A love!
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Question in attachment
kiruha [24]

Answer:

1. a= 7, A = 49 degrees

Side A = 7 , Side B = 24, Side C = 25

A= 49 degrees, C = 90 degrees , B=41

2. A= 4, B = 6.9, C=8

A= 22 degrees, B = 68, C= 90

3. A= 7, B = 14.4, C=16

A= 45 , B=45  , C=90

6 0
3 years ago
Describe a sequence of transformations that can be performed to polygon ABCDE to prove that it is similar to polygon FGHIJ
maxonik [38]

Answer:

answer below

Step-by-step explanation:

ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ

AB // FG slope: -2 , √20:√5 = 2: 1

BC // GH // X axis 8:4 = 2:1

CD // HI, slope= 1 , √8:√2 = 2:1

DE // IJ // x axis, 4:2 = 2:1

EA // JF // y axis, 2:1

8 0
2 years ago
Two chemicals A and B are combined to form a chemical C. The rate, or velocity, of the reaction is proportional to the product o
Keith_Richards [23]

Answer:

  32.1 g

Step-by-step explanation:

In each 3 grams of C, there are 2 grams of A and 1 gram of B. So, for some amount C, the amount remaining of A is 40 -(2C/3), and the amount remaining of B is (50 -C/3). Since the reaction rate is proportional to the product of these amounts, we have ...

  C' = k(40 -2C/3)(50 -C/3) = (2k/9)(60 -C)(150 -C) . . . for some constant k

This is separable differential equation with a solution of the form ...

  ln((150 -C)/(60 -C)) = at + b

We know that C(0) = 0, so b=ln(150/60) = ln(2.5). And we know that C(10) = 20, so ln(130/40) = 10a +ln(2.5) ⇒ a = ln(1.3)/10

Then our equation for C is ...

  ln((150 -C)/(60 -C)) = t·ln(1.3)/10 +ln(2.5)

__

For t=20, this is ...

  ln((150 -C)/(60 -C)) = 2ln(1.3) +ln(2.5) = ln(2.5·1.3²) = ln(4.225)

Taking antilogs, we have ...

  (150 -C)/(60 -C) = 4.225

  1 +90/(60 -C) = 4.225

  C = 60 -90/3.225 ≈ 32.093 . . . . . grams of product in 20 minutes

In 20 minutes, about 32.1 grams of C are formed.

7 0
3 years ago
an electric wire which is 0.12 m long is cut into 3 pieces of the same length.How long is each pieces?​
grigory [225]

Answer:

0.04m

Step-by-step explanation:

0.12/3=0.04

6 0
3 years ago
Read 2 more answers
I decide to bake some cakes.I need 150g of flour for 12 cakes.How much flour do I need for 30 cakes?
blagie [28]
150 / 12 = 11.6666666667
11.6666666667 x 30 = approximately 350g of flour for 30 cakes
7 0
3 years ago
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