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Gekata [30.6K]
3 years ago
9

A 20-foot ladder leans up against the side of a building so that the foot of the ladder is 10 feet from the base of the building

. How far up the
building does the ladder reach? Round your answer to the nearest tenth.
18.1
17.3
15.9
16.4
Mathematics
1 answer:
harina [27]3 years ago
6 0

Answer:

17.3

Step-by-step explanation:

To solve this equation, you need to use the pythagorean theorem which is:

a^{2} +b^{2}= c^{2}

a= length

b= height

c= hypotenuse

First, substitute in your values for the equation:

10^2+b^{2} =20^{2}

Then, use the squares in the equation:

100+b^{2} =400

Then, subtract 100 from both sides to isolate b:

b^{2} =300

Finally, square root both sides to get your answer:

b=17.3205080757

Then round to the nearest tenth which gives you 17.3.

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F(x) = 3x - 2<br><br> f(x) = 0, x=?
podryga [215]

Answer:

2/3 =x

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f(x) = 3x - 2

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8 0
2 years ago
Read 2 more answers
PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Andrew [12]

Answer:

(a) 1825 = 2.25x + (2.25-1)(x -108)

(b) 560 mi/h

Step-by-step explanation:

(a) distance = speed·time

The first plane's speed is x. The distance it travels in 2.25 hours is 2.25x.

The second plane's speed is x-108. It travels only 1.25 hours (since it started an hour later). The distance it travels is then (2.25 -1)(x -108).

The problem statement tells us the total of the distances traveled by the two planes is 1825 miles, so we can write the equation ...

... 1825 = 2.25x + (2.25 -1)(x -108)

(b) Simplifying the equation gives ...

... 1825 = 3.50x -135

To solve this 2-step equation, we add 135, then divide by 3.50.

.. 1960 = 3.50x

... 1960/3.50 = x = 560

The first airplane's speed is 560 mph.

<u>Check</u>

In 2.25 hours, the first plane travels (560 mi/h)·(2.25 h) = 1260 mi.

In 1.25 hours, the second plane travels (452 mi/h)·(1.25 h) = 565 mi.

Then 2.25 hours after the first plane leaves, the planes are 1260 +565 = 1825 miles apart, as given in the problem statement.

3 0
3 years ago
Read 2 more answers
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