Answer:
f(x-3)= x^2 -11x +24
Step-by-step explanation:
We want to find an equivalent expression for f(x-3)
To do this, we can simply substitute every 'x' variable in f(x) by 'x-3'
Therefore f(x-3)= (x-3)^2 -5*(x-3)
Lets re arrange the expression by grouping terms.
f(x-3)=x^2 - 6x +9 -5x + 15
f(x-3)= x^2 -11x +24
Are there any answer choices?
Answer:
x1, x2 = 4.74 , -2.74
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 2x - 13
a = 1 b = -2 c = -13
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1
x1 = (2 + √ (4 + 52)) / 2
x1 = (2 + √ 56 ) / 2
x1 = (2 + 7.48) / 2
x1 = 9.48 / 2
x1 = 4.74
x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1
x2 = (2 - √ (4 + 52)) / 2
x2 = (2 - √ 56 ) / 2
x2 = (2 - 7.48) / 2
x2 = -5.48 / 2
x2 = -2.74
4p - 2 when p=8
(4 x 8) - 2
32 - 2
30
answer: 30
hope it helped :)
