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Alenkasestr [34]

3 years ago

13

A group of 20 students are going to watch a basketball game. It cost $10 for 4 students to watch a game. How much will the group

pay?

1 answer:

ivolga24 [154]3 years ago

6 0

They will pay 15 dollars

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The unit measure that is appropriate would be Cubic meters

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2 years ago

Simplify fully e x e x e x f/ e x e x f x f

mel-nik [20]

Given:

The given expression is

$\dfrac{e\times e\times e\times f}{e\times e\times f\times f}$

To find:

The simplified form of given expression.

Solution:

We have,

$\dfrac{e\times e\times e\times f}{e\times e\times f\times f}$

The common factors in numerator and denominator are e, e, f.

Cancel out the common factors.

$=\dfrac{e}{f}$

Therefore, the required expression is $\dfrac{e}{f}$ .

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3 years ago

Question is worth 25 points what is 15 squared?

makkiz [27]

The answer is 225
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4 years ago

Ill mark brainlist plss help

Lynna [10]

Answer:

it will be 14.10 because 2.35x 6 equals 14.10$

Step-by-step explanation:

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3 years ago

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horrorfan [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

b

$h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

c

$h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

Step-by-step explanation:

From the question we are told that

$h(x) = x^2 + x + 5$

and

$g(x) = \sqrt[4]{x} + 3$

Considering first question

Now we are told g(h(x))

i.e

$g(h(x)) = [x^2 + x + 5 ]^{\frac{1}{4} } + 3$

=> $g(h(x)) = \sqrt[4]{x^2 + x +5} + 3$

Considering second question

Now we are told h(g(x))

i.e

$h(g(x)) = [x^{\frac{1}{4} } + 3]^2 + x^{\frac{1}{4} } + 3 + 5$

=> $h(g(x)) = x^{\frac{1}{2} } + 6x^{\frac{1}{4} } + 9+ x^{\frac{1}{4}} + 8$

=> $h(g(x)) = x^{\frac{1}{2}} + 7x^{\frac{1}{4}} + 17$

=> $h(g(x)) = \sqrt{x} + 7\sqrt[4]{x} + 17$

Considering third question

$h(h(x))= [x^2 + x + 5]^2 + [x^2 + x + 5 ] + 5$

=> $h(h(x)) = [x^2 + x + 5 ]^2 + x^2 + x + 10$

8 0

3 years ago