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laiz [17]
3 years ago
9

Angela began studying at 3:17 P.M. She studied until 4:22 P.M. How long did Angela study?

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
7 0

Answer:

1hr 5mins

Step-by-step explanation:

thanks. for the free points

3 17 to 4 17 one HR

4 17 to 4 22 5 mins

total is one hour plus five mins

so 1 hr 5 mins

andre [41]3 years ago
7 0

Answer:

1 hour and 5 minutes

Step-by-step explanation:

Between 4:22 pm and 3:17 pm, 1 hour has passed.

3:17 + 1 hour = 4:17

Between 4:17 pm and 4:22 pm, 5 minutes has passed.

4:17 + 5 minutes = 4:22

Therefore, Angela has studied for 1 hour and 5 minutes.

I hope this helps!

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There's 6 antinodes here.

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F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

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Answer:

Measure of angle A is 65 degrees and measure of angle B is 37 degrees.

Step-by-step explanation: First add all of the degrees of excluding x (4+(-9)) which is -5. Then subtract that from 180 since that is the sum of all the angles in a triangle which gives you 185. Then divide it by the number of "x's" that there are which is 5 which gives you 37. So angle B is x which is 37 degrees and angle a is 2(37)-9 which is 65 degrees. Hope this helps.

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Answer:

It is B.$159.65


Step-by-step explanation:

I got it the test

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