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uranmaximum [27]
3 years ago
9

Which two inequalities to compare |-5| and 4?

Mathematics
1 answer:
lilavasa [31]3 years ago
7 0

Answer:

|-5|>4

Step-by-step explanation:

Negative 5 in absolute value is 5 since any number in absolute value turns out positive or at the very least 0. 5 is greater than 4, so |-5|>4.

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 it would be the third one, 2/3
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Find the perimeter and area of rectangle ABCD.
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Add up all the sides which should equal 32
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Prove the divisibility:<br><br>45^45·15^15 by 75^30
garri49 [273]

Answer:

3^{75}.

Step-by-step explanation:

We have been an division problem: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(9*5)^{45}=9^{45}*5^{45}

15^{15}=(3*5)^{15}=3^{15}*5^{15}

75^{30}=(15*5)^{30}=15^{30}*5^{30}

Substituting these values in our division problem we will get,

\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}

\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}

\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}

\frac{3^{105}*5^{60}}{3^{30}*5^{60}}

\frac{3^{105}}{3^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{105}}{3^{30}}=3^{105-30}

3^{105-30}=3^{75}

Therefore, our resulting quotient will be 3^{75}.

7 0
3 years ago
Pls help is due for today pls
pentagon [3]

Answer:

Part A: The rate of change was greater in case of the graph.

Part B: The figure shows the graph of function A in Redline and Function B in blue line

Part C : Initial value of function B is greater than Function A.

Step-by-step explanation:

Here, Function A show graph of a line and Function show table show a set of value of x and y.

Part A). Which function show greater rate of change.

The slope of line is given by m = \frac{Y2-Y1}{X2-X1}

For function A:

Given graph passes through points (04) and (2,12)

The slope of line is m=\frac{12-4}{2-0}

                                   =\frac{8}{2}

                                   = 4

For function B:

Given the table has points (012) and (2,14)

The slope of line is m=\frac{14-12}{2-0}

                                   =\frac{2}{2}

                                   = 1

Therefore, The rate of change was greater in case of graph.

Part B). Plot the graph of a function B onto the graph of a function A

The figure shows the graph of function A in Redline and Function B in blueline

Line of function A is more tilted toward the y-axis than Line of function B.

Therefore, Rate of change of function A is greater than Function B.

Part C). Which function has greater initial value?

For function A:

From the graph of part B,

When x=0 y=4

For function B:

From the graph of part B,

When x=0 y=12

Therefore, Initial value of function B is greater than Function A.

5 0
3 years ago
calvin and 4 of his friends want to share 4 pounds of nuts equally.write an expression to show the fraction of the nuts each fri
PilotLPTM [1.2K]
4/5

The 4 is how many pounds of nuts there are and dividing by 5 shows that you are sharing the nuts equally amongst the 5 friends.
5 0
3 years ago
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