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kogti [31]
3 years ago
8

2. A computer valued at $6500 depreciates at the rate of 14.3% per year. a. Write a function that models the value of the comput

er. b. Find the value of the computer after 3 years
Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

$4088.5

Step-by-step explanation:

Given data

Price a =  $6500

Rate of depreciation r= 14.3%

Time x= 3 years

The exponential function Decay is described as

y= ab^x

For decay

b= 1-r

a.

Hence the exponential function that model the value of the computer is

y=a(1-r)^x

b.

y= 6500(1-0.143)^3

y= 6500*(0.857)^3

y= 6500*0.629

y=$4088.5

Hence the value of the computer after 3 years is $4088.5

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<h2>Explanation:</h2><h2></h2>

In this case we have the following expression:

6x^2+10

We know that Karen was trying to factor out this and she found that the greatest common factor of these terms was 2, in other words we can write this expression as:

2(3x^2+5)

An area model for this expression could be the area of a rectangle that has the following dimensions:

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So the area model can be written as:

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Read 2 more answers
2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

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