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ludmilkaskok [199]
3 years ago
11

F(x)= x squared + 6x + 8

Mathematics
1 answer:
defon3 years ago
4 0

Answer: (x+4) (x+2)

Step-by-step explanation:

x^2 + 2x + 4x +8

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1/2 sq. unit 1/2 sq. unit 1 sq. unit 1/2 sq. unit 1/2 sq. unit What is the area of the entire rectangle in square units? Explain
neonofarm [45]

Answer:

  • 3 sq. units

Step-by-step explanation:

<u>Entire area is the sum of areas of sections:</u>

  • A = 1/2 + 1/2 + 1 + 1/2 + 1/2 =
  • 1+ 4*1/2 =
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4 0
3 years ago
PLEASE HELP! giving BRAINLIEST AND GIVE CORRECT ANSWER AND EXPLAIN!
11111nata11111 [884]

The exercise is basiacally asking for the perimeter of the garden. The perimeter of a rectangle is twice the sum of its dimensions, so we have

P=2(6+11)=2\cdot 17=34

7 0
3 years ago
Of all the students enrolled at the American dream, 9% are playing a music instrument. There are 330 students in ADS. How many s
Genrish500 [490]
Exactly 29.7, but you can't have 7/10 of a student so you round to 30. So 30 students are playing a music instrument because 330 times 0.09 is about 30
5 0
3 years ago
Nidhi is allowed to watch 2.5 hours of TV on Saturday If her favorite Tv show lasts for 24 minutes each, how many full episodes
bekas [8.4K]

Answer:

6 full episodes

Step-by-step explanation:

You will need to convert 2.5 hours to minutes and divide by 24. Round to the nearest whole number.

4 0
2 years ago
In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
Read 2 more answers
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