Answer:
77/2 is 38.5 if that is what u were asking
Step-by-step explanation:
The trigonometric ratios show that the angle FHE is 48.59°.
<h3>RIGHT TRIANGLE</h3>
A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.
The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.
The Pythagorean Theorem says:
. And the main trigonometric ratios are:

It is important to remember that the sum of internal angles for any triangle is 180°.
From the question, it is possible to see 2 right triangles (HGF and FHE).
You can find the hypotenuse of the triangle HGF from the trigonometric ratio: sen Θ

The hypotenuse of triangle HGF is one of legs for the triangle FHE. The, you can find the angle FHE from the trigonometric ratio: tan β. Thus,

Learn more about trigonometric ratios here:
brainly.com/question/11967894
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The answer is 21900
BUT if we count leap years it would be 21915 because there would be 5 leap years
Answer:
x=1
Step-by-step explanation:
log2( x^2 -x+2) = 1+2log2(x)
Rewriting 1 as log2(2)
log2( x^2 -x+2) = log2(2)+2log2(x)
We know that a log b = log a^b
log2( x^2 -x+2) = log2(2)+log2(x^2)
we know log a + log b = log (ab)
log2( x^2 -x+2) = log2(2*x^2)
Since the bases are the same the terms inside must be equal
x^2 -x+2 = 2x^2
Subtract 2x^2 from each side
-x^2 -x+2 = 0
Multiply by -1
x^2 +x-2 = 0
Factor
(x+2)(x-1)=0
Using the zero product property
x+2 = 0 x-1=0
x=-2 x=1
Checking the solutions
log2( x^2 -x+2) = 1+2log2(x)
X cannot be negative because 2 log2(x) cannot be negative
log2( 1^2 -1+2) = 1+2log2(1)
x=1